FINEUPLOAD将ID作为参数传递 [英] FINEUPLOAD pass the ID as parameter

问题描述

我有这个divs

<div id="thumbnail-uploader_1" class="thumbnail-uploader">
<div id="thumbnail-uploader_2" class="thumbnail-uploader">

和这个Jquery调用

and this Jquery call

$('.thumbnail-uploader').fineUploader({
request: {
    endpoint: '/core/ajax/add_avatar.php',
    params: {
    one: function() {
        return this.id;
     }
    }
},
multiple: false,
validation: {
    allowedExtensions: ['jpeg', 'jpg', 'gif', 'png'],
    sizeLimit: 551200 // 50 kB = 50 * 1024 bytes
},
text: {
    uploadButton: 'Klikněte nebo sem přetáhněte soubor'
}
}).on('complete', function(event, id, fileName, responseJSON) {
if (responseJSON.success) {
    $(this).append('<img src="/uploads/categories/' + fileName + '" alt="' + fileName + '">');
    $('.qq-upload-list').fadeOut(2500);
}
});

我要做的就是传递使用的上载器的ID.但是通过此调用，当我尝试在作为处理程序的"add_avatar.php"中使用参数"one"时，得到了未定义的值.我在那边使用全局数组REQUEST来检查值是否通过.但未定义.

all i want to do is to pass the ID of the used uploader. but with this call, i got undefined value of the parameter "one" when i try to use it in "add_avatar.php" which is handler. i use the global array REQUEST over there to check if the value pass. but its undefined.

有人知道如何在我的PHP脚本中传递ID吗?我将在那里有更多该上传器的实例，因此我必须检查更改头像时的记录.

does anyone have some idea how to pass the ID in my php script? i will have more instances of this uploader there so i have to check for which record im changing the avatar.

推荐答案

由于您使用的是jQuery，也许这就是您想要的.

Since you are using jQuery, maybe this is what you are looking for.

return $(this).attr('id');

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