打开动态链接时如何重定向到特定屏幕? [英] How to redirect to a certain screen when opening a dynamic link?

问题描述

我正在开发可以接收Firebase动态链接的应用程序.我想要的是当用户单击动态链接时，应用程序将其重定向到特定的UIViewController.因此，我的AppDelegate.swift文件中有一个类似于以下代码的代码:

@available(iOS 9.0, *)
    func application(_ app: UIApplication, open url: URL, options: [UIApplication.OpenURLOptionsKey : Any]) -> Bool {
        //return GIDSignIn.sharedInstance().handle(url)
        return application(app, open: url, sourceApplication: options[UIApplication.OpenURLOptionsKey.sourceApplication] as? String, annotation: "")
    }

    func application(_ application: UIApplication, open url: URL, sourceApplication: String?, annotation: Any) -> Bool {
        // On progress
        if let dynamicLink = DynamicLinks.dynamicLinks().dynamicLink(fromCustomSchemeURL: url) {
            print("open url = open dynamic link activity")
            print("url = \(dynamicLink)")
            let destinationVC = UIStoryboard(name: "DynamicLink", bundle: nil).instantiateViewController(withIdentifier: "DynamicLinkView") as? DynamicLinkVC
            self.window?.rootViewController?.navigationController?.pushViewController(destinationVC!, animated: true)
        } else {
            print("open url = none")
        }
        return GIDSignIn.sharedInstance().handle(url)
    }

func application(_ application: UIApplication, continue userActivity: NSUserActivity, restorationHandler: @escaping ([UIUserActivityRestoring]?) -> Void) -> Bool {
        // On progress
        let handled = DynamicLinks.dynamicLinks().handleUniversalLink(userActivity.webpageURL!) { (dynamiclink, error) in
            print("dynamic link = \(dynamiclink)")
        }

        if handled {
            let destinationVC = UIStoryboard(name: "DynamicLink", bundle: nil).instantiateViewController(withIdentifier: "DynamicLinkView") as? DynamicLinkVC
            self.window?.rootViewController?.navigationController?.pushViewController(destinationVC!, animated: true)
        }

        return handled
    }

因此，当我单击链接时会发生什么情况，该应用程序立即打开，但没有重定向到所需的所需UIViewController(在本例中为destinationVC).它像往常一样直接转到登录页面.但是在调试区域中，链接看起来像这样=

动态链接=可选(https://xxxx]，匹配类型:唯一，minimumAppVersion:不适用，匹配消息:(空)>)

不幸的是，当应用不是由Xcode构建时，我无法记录日志消息.

我对此感到非常困惑，我的代码有什么问题?我是iOS开发的新手，所以不确定在哪里做错了.如果您需要更多信息，请随时提出，我们将为您提供.任何帮助，将不胜感激.谢谢.

解决方案

如果您的其余代码工作正常，并且在导航到另一个视图控制器时遇到问题，那么该解决方案将为您服务. /p>

如果您要打开特定的 ViewController ，请在点击动态链接的同时更新用restorationHandler编写的代码，下面的更新代码将帮助您重定向/导航到特定的View Controller

func application(_ application: UIApplication, continue userActivity: NSUserActivity, restorationHandler: @escaping ([UIUserActivityRestoring]?) -> Void) -> Bool {
        // On progress
        let handled = DynamicLinks.dynamicLinks().handleUniversalLink(userActivity.webpageURL!) { (dynamiclink, error) in
            print("dynamic link = \(dynamiclink)")
        }

    if handled {

             let mainStoryboardIpad : UIStoryboard = UIStoryboard(name: "DynamicLink", bundle: nil)
             if let initialViewController : UIViewController = (mainStoryboardIpad.instantiateViewController(withIdentifier: "DynamicLinkView") as? DynamicLinkVC) {
                    self.window = UIWindow(frame: UIScreen.main.bounds)
                    self.window?.rootViewController = initialViewController
                    self.window?.makeKeyAndVisible()
               }

        return handled
    }

希望这可以解决您的问题.

I'm developing an app that can receive Firebase's Dynamic Link. What I want is when a user click a Dynamic Link, the app redirects it to a certain UIViewController. So I have a code that looks like this on my AppDelegate.swift file:

@available(iOS 9.0, *)
    func application(_ app: UIApplication, open url: URL, options: [UIApplication.OpenURLOptionsKey : Any]) -> Bool {
        //return GIDSignIn.sharedInstance().handle(url)
        return application(app, open: url, sourceApplication: options[UIApplication.OpenURLOptionsKey.sourceApplication] as? String, annotation: "")
    }

    func application(_ application: UIApplication, open url: URL, sourceApplication: String?, annotation: Any) -> Bool {
        // On progress
        if let dynamicLink = DynamicLinks.dynamicLinks().dynamicLink(fromCustomSchemeURL: url) {
            print("open url = open dynamic link activity")
            print("url = \(dynamicLink)")
            let destinationVC = UIStoryboard(name: "DynamicLink", bundle: nil).instantiateViewController(withIdentifier: "DynamicLinkView") as? DynamicLinkVC
            self.window?.rootViewController?.navigationController?.pushViewController(destinationVC!, animated: true)
        } else {
            print("open url = none")
        }
        return GIDSignIn.sharedInstance().handle(url)
    }

func application(_ application: UIApplication, continue userActivity: NSUserActivity, restorationHandler: @escaping ([UIUserActivityRestoring]?) -> Void) -> Bool {
        // On progress
        let handled = DynamicLinks.dynamicLinks().handleUniversalLink(userActivity.webpageURL!) { (dynamiclink, error) in
            print("dynamic link = \(dynamiclink)")
        }

        if handled {
            let destinationVC = UIStoryboard(name: "DynamicLink", bundle: nil).instantiateViewController(withIdentifier: "DynamicLinkView") as? DynamicLinkVC
            self.window?.rootViewController?.navigationController?.pushViewController(destinationVC!, animated: true)
        }

        return handled
    }

So what happened when I click the link the app opens up immediately but it doesn't redirects to the desired UIViewController that I wanted (in this case destinationVC). It directly went to the login page as usual. But in the debug area, the link appears like this =

dynamic link = Optional(https://xxxx], match type: unique, minimumAppVersion: N/A, match message: (null)>)

Unfortunately I couldn't record the log messages when the app is not built by Xcode.

I'm very confused by this, what's wrong with my code? I'm new to iOS development so I'm not sure where did I do wrong. If you need more information feel free to ask and I will provide it to you. Any help would be appreciated. Thank you.

解决方案

If your rest-of-code is working fine, and you are just facing issue while navigating to another view controller, then this solution will work for you.

If you want to open particular ViewController, while clicking on dynamic link, then update your code written within restorationHandler, below updated code will help you to redirect/navigate to particular View Controller

func application(_ application: UIApplication, continue userActivity: NSUserActivity, restorationHandler: @escaping ([UIUserActivityRestoring]?) -> Void) -> Bool {
        // On progress
        let handled = DynamicLinks.dynamicLinks().handleUniversalLink(userActivity.webpageURL!) { (dynamiclink, error) in
            print("dynamic link = \(dynamiclink)")
        }

    if handled {

             let mainStoryboardIpad : UIStoryboard = UIStoryboard(name: "DynamicLink", bundle: nil)
             if let initialViewController : UIViewController = (mainStoryboardIpad.instantiateViewController(withIdentifier: "DynamicLinkView") as? DynamicLinkVC) {
                    self.window = UIWindow(frame: UIScreen.main.bounds)
                    self.window?.rootViewController = initialViewController
                    self.window?.makeKeyAndVisible()
               }

        return handled
    }

Hope this will resolve your issue.

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