Firebase函数onWrite未被调用 [英] Firebase function onWrite not being called

问题描述

我正在尝试使用Firebase Functions实现触发器，该触发器复制数据库中的某些数据.我想在votes/user/vote观看所有添加的内容，结构为:

I'm trying to implement a trigger using Firebase Functions, that duplicates some data in the database. I want to watch all additions at votes/user/vote, the structure is:

我尝试的代码是:

const functions = require('firebase-functions');
const admin = require('firebase-admin');

admin.initializeApp(functions.config().firebase);

exports.duplicateFeedback = functions.database.ref('/votes/{userId}/voteId')
    .onWrite(event => {
        const userId = event.params.userId;
        const voteId = event.data.key();
        const vote = event.data.val();
        console.log(`New feedback from user ${userId}: { description: "${vote.feedback}", score: ${vote.rating}}`);

        return;
    });

但是我什至无法触发它.任何线索我的函数有什么问题吗?我敢打赌，这与参考资料有关，但我无法弄清楚到底是什么.

But I can't even get it triggered.. Any clues what's wrong with my function? I bet is related with the reference, but I can't figure out what exactly.

推荐答案

现在，该功能是通过写入

Right now, the function is triggered by a write to

exports.duplicateFeedback = functions.database.ref('/votes/{userId}/voteId')

这将由类似这样的触发:

which would be triggered by something like this:

votes: {
    00000_josemi_foo: {
        voteId: {
            // data
        }
    }
}

但是您并没有在寻找voteId的孩子，而是在寻找{userId}的任何孩子，例如-33，因此您需要使用通配符:

But you're not looking for the child voteId, you're looking for any child of {userId}, such as -33, so you need to use a wildcard:

exports.duplicateFeedback = functions.database.ref('/votes/{userId}/{voteId}')

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