如何比较Firebase中的UID和另一个子键? [英] How to compare UID and another child key in Firebase?

问题描述

我想用Android中的相同键连接当前用户ID，但是在另一个子节点中，我从过去的两天开始搜索，但是找不到任何解决方案，我只能获取uid，而无法获取其他解决方案我想要比较以获取数据的ID.

I want to connect the current user id with the same key in Android, but in another child node, I am searching from tow days, but cant find any solution, I can only get uid, but can't get the other id which I want to compare for retrieving data.

有人可以帮助我如何找到在另一个字段中实际上是uid的子项吗?谢谢.

Can any one help me how to find the child key which is actually uid in another field? Thanks.

推荐答案

用英语:

如果DatabaseReference指向users节点，则使用getParent()转到根节点，然后使用getChild(<UID here>)获取对该节点的引用.

If your DatabaseReference is pointing at the users node, then use getParent() to go to the root node, then use getChild(<UID here>) to get a reference to that node.

Hindi Mein:

Hindi Mein:

琼脂aapke DatabaseReference users节点par ishaara kar raha hai，toh getParent () ka upayog karein，根节点tak jaane ke lie.菲尔getChild("UserInfo").getChild(<UID here>) us node tak jaane ke lie.

agar aapke DatabaseReference users node par ishaara kar raha hai, toh getParent () ka upayog karein, root node tak jaane ke lie. Phir getChild("UserInfo").getChild(<UID here>) us node tak jaane ke lie.

在代码中:

String uid = "CP9l8L1viLU77KrEOEDj2tNRCYq2"
DatabaseReference mRef = FirebaseDatabase.getInstance().getReference("users");
DatabaseReference refToYourUserid = mRef.getParent().getChild("UserInfo").getChild(uid);

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