如何检查用户名在Firebase中是否唯一 [英] How to check if usernames are unique in Firebase

问题描述

我有一个功能(尚未完成)，该功能应检查用户名在Firebase数据库中是否已经存在/唯一.我已经在Google上搜索了如何实施此方法，并设法获得了以下信息.不幸的是，它不起作用，我什至没有任何console.logs.感谢您的帮助-我到底在做什么错?

I have a function (not finished yet) that should check if a username already exists/is unique in my Firebase database. I have searched Google on how to implement this and I have managed to get the below. Unfortunately, it doesn't work and I don't even get any console.logs. Any help is appreciated - what exactly am I doing wrong?

 onChangeUsername = (event) => {

var oldError = {...this.state.error};

firebase.database().ref().child("Usernames").orderByValue().once('value', (snapshot) => {
  var exists = (snapshot.val() !== null);
  console.log(exists);
  console.log("hello");
});


if(this.state.validation.username.unique===true)
{oldError.username = "This username is already taken"}

else if((event.nativeEvent.text.length<this.state.validation.username.min) || (event.nativeEvent.text.length>this.state.validation.username.max) )
{oldError.username = "Username should be between " + this.state.validation.username.min + " and " + this.state.validation.username.max + " characters" ;}


else oldError.username = "";



this.setState({ username: event.nativeEvent.text, error:oldError })
}

我的数据库结构如下:

Database:{ Usernames: {uid1: username1, uid2: username2}}

****问题更新**** 在弗兰克发表评论后，我将代码更改为以下代码.它仍然不起作用，但是我他发现了一些需要修复的错误:

****Question Update **** After Comments from Frank, I have changed my code to the following. It still doesn't work, but my he has spotted a couple of errors that needed fixing:

onChangeUsername = (event) => {

    var oldError = {...this.state.error};

    firebase.database().ref().child("Usernames").orderByKey().equalTo("Username1").once('value', (snapshot) => {
      var exists = (snapshot.val() !== null);
      console.log(exists);
      console.log("hello");
    });


    if(this.state.validation.username.unique===true)
    {oldError.username = "This username is already taken"}

    else if((event.nativeEvent.text.length<this.state.validation.username.min) || (event.nativeEvent.text.length>this.state.validation.username.max) )
    {oldError.username = "Username should be between " + this.state.validation.username.min + " and " + this.state.validation.username.max + " characters" ;}


    else oldError.username = "";



    this.setState({ username: event.nativeEvent.text, error:oldError })
  }

和我的数据库如下:

Database:{ Usernames: {Username1: uid1, Username2: uid2}}

推荐答案

您在查询中缺少比较项:

You're missing a comparison in your query:

firebase.database().ref().child("Usernames").equalTo("Username1").orderByValue()

我建议顺便说一句反转数据结构.如果您希望用户名唯一，请使用这些名称作为父节点中的键:

I recommend btw inverting the data structure. If you want user names to be unique, use those as the keys in the parent node:

Database:{ 
  Usernames: {
    Username1: uidOfUserWithUsername1, 
    Username2: uidOfUserWithUsername2 
  }
}

这样，由于您不需要查询，因此您的查询将变得更简单，更快捷.此外，该值现在使您可以轻松查找有关使用此用户名的用户的更多信息.

This way your lookups will be simpler and fast, since you don't need a query. In addition, the value will now allow you to easily look up more information on the user who claimed this user name.

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