无法从异步函数返回值.为什么? [英] Can't return value from async function. Why?
问题描述
我想从currentUserName()函数返回名称,但是我得到了ZoneAwarePromise.这是我的代码:
I want to return name from currentUserName() function, but I got ZoneAwarePromise. Here is my code:
currentUserName() {
var firebaseData = firebase.database().ref('users');
var userid = this.afAuth.auth.currentUser.uid;
var promises = [];
var name;
var promise = firebaseData.orderByKey().once('value').then(function
(snapshot) {
snapshot.forEach(function (childSnapshot) {
if (childSnapshot.key === userid) {
name = childSnapshot.val().displayName;
}
});
return name;
});
promises.push(promise);
return Promise.all(promises).then(function(val) { return val; });
}
推荐答案
您不应使用Promise.all,因为只有一个诺言可以被调用,即firebaseData.orderByKey().once('value')
.
You should not use Promise.all since there is only one promise to be called, i.e. firebaseData.orderByKey().once('value')
.
once()方法返回一个诺言(请参见 doc ),将在对实时数据库的异步查询完成后解决.
The once() method returns a promise (see the doc) that will be resolved when the asynchronous query to the Real Time Database will be completed.
因此,您的currentUserName()
函数应返回带有查询结果的Promise,并且在调用此函数时应使用then()
.
So your currentUserName()
function shall return a promise with the result of the query and you should use then()
when you call this function.
因此,您应该按以下方式编写函数:
So, you should write your function as follows:
function currentUserName() {
var firebaseData = firebase.database().ref('users');
var userid = this.afAuth.auth.currentUser.uid;
return firebaseData.orderByKey().once('value').then(function(snapshot) {
var name;
snapshot.forEach(function (childSnapshot) {
if (childSnapshot.key === userid) {
name = childSnapshot.val().displayName;
}
});
return name;
});
}
并按如下方式调用它:
currentUserName().then(function(snapshot) {
console.log(snapshot);
});
这篇关于无法从异步函数返回值.为什么?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!