是否可以执行If Else或Switch语句Firestore规则 [英] Is it possible to do a If Else or a Switch Statement Firestore Rules

问题描述

是否有可能在Firestore规则中执行Switch语句或其他操作?

Is it possible to do a Switch Statement or an if else in firestore rules?

我试图搜索它，但是没有找到答案的运气.

I have tried to search for it with no luck of finding an answer.

我尝试过的是

function getTier() {
  return get(/users/$(request.auth.uid)).data.userTier;
}

function canAddProduct() {
  if getTier() == 'UserTier.FREE'
    // Do additional code 
    return doSomethingBasedOnFreeTier();
  else if getTier() == 'UserTier.SILVER'
    // Do additional code 
    return doSomethingBasedOnSilverTier()
  else if getTier() == 'UserTier.GOLD'
    // Do additional code 
    return doSomethingBasedOnGoldTier()
  else if getTier() == 'UserTier.COMPANY'
    // Do additional code 
    return doSomethingBasedOnCompanyTier()
}

任何帮助将不胜感激.

推荐答案

自2020年2月13日起，Firestore现在支持三元运算符

As of Feb 13, 2020 Firestore now supports the ternary operator

https://firebase.google.com/support/release -notes/security-rules#february_13_2020

以下是可用运算符的文档(三元位于底部)

Here's the documentation for the available operators (ternary is at the bottom)

https://firebase.google.com/docs/rules/rules -language#building_conditions

从问题中获取示例代码，可以通过使用嵌套的三元运算符集来实现解决方案

Taking the example code from the question, the solution can be achieved by using a nested set of ternary operators

function getTier() {
  return get(/users/$(request.auth.uid)).data.userTier;
}

function canAddProduct() {
  return getTier() == 'UserTier.FREE' ?
    doSomethingBasedOnFreeTier() :
    (
      getTier() == 'UserTier.SILVER' ?
        doSomethingBasedOnSilverTier() :
        (
          getTier() == 'UserTier.GOLD' ?
            doSomethingBasedOnGoldTier() :
            (
              getTier() == 'UserTier.COMPANY' ?
                doSomethingBasedOnCompanyTier() :
                null
            ) 
        )
    )
}

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