Flask视图显示400错误而不是带有表单的模板 [英] Flask view shows 400 error instead of template with form

问题描述

我试图显示一个带有表单的页面，然后在提交表单时将Player添加到数据库中.但是，我无法查看该表单，因为浏览器始终显示400 Bad Request错误.其他帖子表明这可能是因为表单输入的名称与我从request.form获取的键不匹配，但是我所有的键都匹配了.为什么会出现此错误?

I'm trying to display a page with a form, then add a Player to the database when the form is submitted. However, I can't view the form because the browser always shows a 400 Bad Request error. Other posts indicate that this could be because the name of the form input doesn't match the key I get from request.form, but all my keys match. Why do I get this error?

<form method="post">
    {{ form.hidden_tag() }}
    <input name="name">
    <input name="available">
    <input type="submit">
</form>

@app.route('/addplayer', methods=['GET', 'POST'])
def addplayer():
    connect('basketball_contracts', host='localhost', port=27017)
    n = request.form['name']
    a = request.form['available']
    post= Post(
        name=n,
        available=a
    )
    post.tags = ['test']
    post.save()
    return render_template('addplayer.html', form=form)

推荐答案

您的视图接受GET和POST请求. request.form仅在POST上填写.如果尝试访问不存在的密钥，则会引发400错误.最初GET页面时，没有键.

Your view accepts GET and POST requests. request.form is only filled out on POST. If you try to access a key that doesn't exist, it raises a 400 error. No keys will exist when you GET the page initially.

常见的模式是保护在if request.method == 'POST'块中需要request.form的代码.处理POST请求后返回重定向，否则返回渲染的模板.

The common pattern for this is to guard code that requires request.form in an if request.method == 'POST' block. Return a redirect after handling the POST request, otherwise return the rendered template.

from flask import url_for, redirect, render_template

@app.route('/addplayer', methods=['GET', 'POST'])
def addplayer():
    if request.method == 'POST':
        Post(
            name=request.form['name'],
            available=request.form['available']
        ).save()
        return redirect(url_for('index'))

    return render_template('addplayer.html')

---

由于您似乎正在使用Flask-WTF，因此可以使用表单的validate_on_submit方法而不是选中method.在这种情况下，您还可以通过表单实例访问数据，并使用该表单为您呈现输入.

---

Since you appear to be using Flask-WTF, you can use the form's validate_on_submit method instead of checking method. In that case, you can also access the data through the form instance, and use the form to render the inputs for you.

from flask import url_for, redirect, render_template

@app.route('/addplayer', methods=['GET', 'POST'])
def addplayer():
    form = AddPlayerForm()

    if form.validate_on_submit():
        Post(
            name=form.name.data,
            available=form.available.data
        ).save()
        return redirect(url_for('index'))

    return render_template('addplayer.html', form=form)

<form method=post>
    {{ form.hidden_tag() }}
    {{ form.name.label}} {{ form.name }}<br>
    {{ form.available.label }} {{ form.available }}<br>
    <input type=submit value="Add Player">
</form>

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