Flutter-如何在中间关闭showDialog小部件 [英] Flutter - How to dismiss a showDialog widget in the middle

问题描述

我有两个同时运行的进程在相同的上下文中彼此独立运行.我们将其命名为A和B.两者都会弹出一个忙碌指示器.

I have two simultaneous processes run independently between each other on the same context. Let's name it A and B. Both popup a busy indicator.

showDialog(... child: Center(child: CircularProgressIndicator()) ...);

完成后，B将弹出一个AlertDialog.有时，如果A花费的时间更长，则在A忙碌指示消失之前会弹出警报对话框.因此，当A完成时，它将关闭警报对话框而不是忙碌指示器.

On finish, B will popup an AlertDialog. Sometimes if A take longer, the alert dialog popup before busy indicator of A is dismissed. So when A finished, it will dismiss the alert dialog not the busy indicator.

Navigator.of(context).pop(data);

如何选择要关闭的showDialog小部件?

How to choose which showDialog widget to dismiss?

推荐答案

也许可以这样工作:

     final GlobalKey navigator1 = GlobalKey<NavigatorState>();
     final GlobalKey navigator2 = GlobalKey<NavigatorState>();

     ...

     _showDialog(context, 'alert1', navigator1);
     _showDialog(context, 'alert2', navigator2);

      ...

    _showDialog(BuildContext context, String text, GlobalKey key) {
      return showDialog(
                  context: context,
                  builder: (BuildContext context) {
                    return AlertDialog(
                      key: key,
                      title: new Text(text),
                      actions: <Widget>[
                        new FlatButton(
                          child: new Text("Close"),
                          onPressed: () {
                        Navigator.pop(key.currentContext);
                      },
                    ),
                  ],
                );
            });
        }

为每个对话框提供一个导航键，然后使用该键关闭所需的对话框.

You give a navigator key for each dialog and use that key to dismiss the dialog you want.

希望有帮助

这篇关于Flutter-如何在中间关闭showDialog小部件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！