如何计算特定字体和大小的字符串长度(以像素为单位)? [英] How to calculate length of string in pixels for specific font and size?

问题描述

如果是字体，例如"Times New Roman"及其大小，例如已知12 pt的字符串长度如何"Hello world"以像素为单位进行计算，也许仅是近似值?

If the font, e.g. "Times New Roman", and size, e.g. 12 pt, is known, how can the length of a string, e.g. "Hello world" be calculated in pixels, maybe only approximately?

我需要执行此操作以对Windows应用程序中显示的文本进行一些手动右对齐，因此我需要调整数字空间以获取对齐方式.

I need this to do some manual right alignment of text shown in an Windows application, so I need to adjust the number spaces to get the alignment.

推荐答案

另一种方法是如下询问Windows:

An alternative is to ask Windows as follows:

import ctypes

def GetTextDimensions(text, points, font):
    class SIZE(ctypes.Structure):
        _fields_ = [("cx", ctypes.c_long), ("cy", ctypes.c_long)]

    hdc = ctypes.windll.user32.GetDC(0)
    hfont = ctypes.windll.gdi32.CreateFontA(points, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, font)
    hfont_old = ctypes.windll.gdi32.SelectObject(hdc, hfont)

    size = SIZE(0, 0)
    ctypes.windll.gdi32.GetTextExtentPoint32A(hdc, text, len(text), ctypes.byref(size))

    ctypes.windll.gdi32.SelectObject(hdc, hfont_old)
    ctypes.windll.gdi32.DeleteObject(hfont)

    return (size.cx, size.cy)

print(GetTextDimensions("Hello world", 12, "Times New Roman"))
print(GetTextDimensions("Hello world", 12, "Arial"))

这将显示:

(47, 12)
(45, 12)

这篇关于如何计算特定字体和大小的字符串长度(以像素为单位)?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！