带范围的foreach不起作用 [英] foreach with range does not work
问题描述
这是我的代码:
function my_function()
{
$states = array('schwarz', 'rot', 'blau');
foreach(range(0, 5) as $number) {
foreach ($states as $state) {
$result = "<img src=\"inventory_images/8.jpg\" onclick=\"changecolor(this)\" name=\"nummer.$number\" />";
$testPath = "transactions/Ordner$number/$state.png";
if (file_exists($testPath)) {
$result = $testPath;
}
}
break;
}
return $result;
}
$imagesPerLine = array(1=>1, 2=>2); $default = 3;
$lines = array(1, 2, 3);
$html="";
foreach ($lines as $line) {
if (!isset($imagesPerLine[$line])) {
$imagesPerLine[$line] = $default;
}
$html.= "<tr>\n";
for ($i = 1; $i <= $imagesPerLine[$line]; $i++) {
$html.=sprintf("<td>%s</td>\n", my_function());
}
$html.="</tr>\n";
}
echo $html;
这是输出:
<tr>
<td><img src="inventory_images/8.jpg" onclick="changecolor(this)" name="nummer.0" /></td>
</tr>
<tr>
<td><img src="inventory_images/8.jpg" onclick="changecolor(this)" name="nummer.0" /></td>
<td><img src="inventory_images/8.jpg" onclick="changecolor(this)" name="nummer.0" /></td>
</tr>
<tr>
<td><img src="inventory_images/8.jpg" onclick="changecolor(this)" name="nummer.0" /></td>
<td><img src="inventory_images/8.jpg" onclick="changecolor(this)" name="nummer.0" /></td>
<td><img src="inventory_images/8.jpg" onclick="changecolor(this)" name="nummer.0" /></td>
</tr>
现在我不知道如何配置我的foreach部分以获取名称值= n + 1.输出应为:
now i dont know how to configure my foreach part to get the name-value = n+1.the output should be:
<tr>
<td><img src="inventory_images/8.jpg" onclick="changecolor(this)" name="nummer.0" /></td>
</tr>
<tr>
<td><img src="inventory_images/8.jpg" onclick="changecolor(this)" name="nummer.1" /></td>
<td><img src="inventory_images/8.jpg" onclick="changecolor(this)" name="nummer.2" /></td>
</tr>
<tr>
<td><img src="inventory_images/8.jpg" onclick="changecolor(this)" name="nummer.3" /></td>
<td><img src="inventory_images/8.jpg" onclick="changecolor(this)" name="nummer.4" /></td>
<td><img src="inventory_images/8.jpg" onclick="changecolor(this)" name="nummer.5" /></td>
</tr>
首先,我想到了休息".或返回$ result;"被放置错了,但我现在不这么认为. 有人可以帮助我更改脚本吗? 谢谢和问候!
firstly i thought, "break;" or "return $result;" is placed wrong, but i dont think so now. could anybody help me to change my script maybe?? thanks and greetings!!
推荐答案
您的逻辑有缺陷.因为您从函数中返回了字符串,并在外部打印出来,所以您需要更改操作方式.当前,您正在执行以下操作:
Your logic is flawed. Because you return the string from your function, and print it outside, you need to change how you are doing it. Currently, you're doing this:
for ($i = 1; $i <= $imagesPerLine[$line]; $i++) {
$html.=sprintf("<td>%s</td>\n", my_function());
}
对我来说听起来很像,您需要使函数用<td>...</td>
包装其内容,然后进行连接.因此,在您的函数内应该执行以下操作:
Sounds to me like you need to make your function wrap its content with <td>...</td>
, and also concatenate. So inside your function you should do:
$result .= "<td>etc etc $number etc etc</td>\n";
将$result = "";
放在该函数的顶部也是一个好习惯.
It would also be good practice to put $result = "";
at the top of that function.
现在,当您返回$result
时,应该将所有内容放到这些循环中,然后通过更改调用循环将它们添加到$html
中:
Now, when you return $result
, you should get all the stuff you put together inside those loops, and you add that to $html
by changing your calling loop:
for ($i = 1; $i <= $imagesPerLine[$line]; $i++) {
$html .= my_function();
}
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