多重处理:为什么在复制列表时与子进程共享一个numpy数组? [英] Multiprocessing: why is a numpy array shared with the child processes, while a list is copied?
问题描述
我使用了此脚本(请参阅末尾的代码)以评估在派生父进程时是共享还是复制了全局对象.
I used this script (see code at the end) to assess whether a global object is shared or copied when the parent process is forked.
简而言之,该脚本创建了一个全局data
对象,并且子进程在data
上进行迭代.该脚本还监视内存使用情况,以评估对象是否已在子进程中复制.
Briefly, the script creates a global data
object, and the child processes iterate over data
. The script also monitors the memory usage to assess whether the object was copied in the child processes.
以下是结果:
-
data = np.ones((N,N))
.在子进程中的操作:data.sum()
.结果:data
被共享(无副本) -
data = list(range(pow(10, 8)))
.子进程中的操作:sum(data)
.结果:data
已被复制. -
data = list(range(pow(10, 8)))
.子进程中的操作:for x in data: pass
.结果:data
已被复制.
data = np.ones((N,N))
. Operation in the child process:data.sum()
. Result:data
is shared (no copy)data = list(range(pow(10, 8)))
. Operation in the child process:sum(data)
. Result:data
is copied.data = list(range(pow(10, 8)))
. Operation in the child process:for x in data: pass
. Result:data
is copied.
由于写时复制,所以预期结果1).我对结果2)和3)感到有些困惑.为什么要复制data
?
Result 1) is expected because of copy-on-write. I am a bit puzzled by the results 2) and 3). Why is data
copied?
脚本
import multiprocessing as mp
import numpy as np
import logging
import os
logger = mp.log_to_stderr(logging.WARNING)
def free_memory():
total = 0
with open('/proc/meminfo', 'r') as f:
for line in f:
line = line.strip()
if any(line.startswith(field) for field in ('MemFree', 'Buffers', 'Cached')):
field, amount, unit = line.split()
amount = int(amount)
if unit != 'kB':
raise ValueError(
'Unknown unit {u!r} in /proc/meminfo'.format(u = unit))
total += amount
return total
def worker(i):
x = data.sum() # Exercise access to data
logger.warn('Free memory: {m}'.format(m = free_memory()))
def main():
procs = [mp.Process(target = worker, args = (i, )) for i in range(4)]
for proc in procs:
proc.start()
for proc in procs:
proc.join()
logger.warn('Initial free: {m}'.format(m = free_memory()))
N = 15000
data = np.ones((N,N))
logger.warn('After allocating data: {m}'.format(m = free_memory()))
if __name__ == '__main__':
main()
详细结果
运行1个输出
[WARNING/MainProcess] Initial free: 25.1 GB
[WARNING/MainProcess] After allocating data: 23.3 GB
[WARNING/Process-2] Free memory: 23.3 GB
[WARNING/Process-4] Free memory: 23.3 GB
[WARNING/Process-1] Free memory: 23.3 GB
[WARNING/Process-3] Free memory: 23.3 GB
[WARNING/MainProcess] Initial free: 25.1 GB
[WARNING/MainProcess] After allocating data: 23.3 GB
[WARNING/Process-2] Free memory: 23.3 GB
[WARNING/Process-4] Free memory: 23.3 GB
[WARNING/Process-1] Free memory: 23.3 GB
[WARNING/Process-3] Free memory: 23.3 GB
运行2个输出
[WARNING/MainProcess] Initial free: 25.1 GB
[WARNING/MainProcess] After allocating data: 21.9 GB
[WARNING/Process-2] Free memory: 12.6 GB
[WARNING/Process-4] Free memory: 12.7 GB
[WARNING/Process-1] Free memory: 16.3 GB
[WARNING/Process-3] Free memory: 17.1 GB
[WARNING/MainProcess] Initial free: 25.1 GB
[WARNING/MainProcess] After allocating data: 21.9 GB
[WARNING/Process-2] Free memory: 12.6 GB
[WARNING/Process-4] Free memory: 12.7 GB
[WARNING/Process-1] Free memory: 16.3 GB
[WARNING/Process-3] Free memory: 17.1 GB
运行3个输出
[WARNING/MainProcess] Initial free: 25.1 GB
[WARNING/MainProcess] After allocating data: 21.9 GB
[WARNING/Process-2] Free memory: 12.6 GB
[WARNING/Process-4] Free memory: 13.1 GB
[WARNING/Process-1] Free memory: 14.6 GB
[WARNING/Process-3] Free memory: 19.3 GB
[WARNING/MainProcess] Initial free: 25.1 GB
[WARNING/MainProcess] After allocating data: 21.9 GB
[WARNING/Process-2] Free memory: 12.6 GB
[WARNING/Process-4] Free memory: 13.1 GB
[WARNING/Process-1] Free memory: 14.6 GB
[WARNING/Process-3] Free memory: 19.3 GB
推荐答案
它们都是写时复制的.您所缺少的是,例如,
They're all copy-on-write. What you're missing is that when you do, e.g.,
for x in data:
pass
data
中包含的每个对象的引用计数都暂时增加1,因为x
依次绑定到每个对象.对于int
对象,CPython中的refcount是基本对象布局的一部分,因此该对象将被复制(您 did 对其进行了更改,因为refcount发生了变化).
the reference count on every object contained in data
is temporarily incremented by 1, one at a time, as x
is bound to each object in turn. For int
objects, the refcount in CPython is part of the basic object layout, so the object gets copied (you did mutate it, because the refcount changes).
要使事情更类似于numpy.ones
情况,请尝试例如
To make something more analogous to the numpy.ones
case, try, e.g.,
data = [1] * 10**8
然后,只有一个唯一对象被列表引用多次(10**8
),因此几乎没有要复制的内容(同一对象的refcount多次增加和减少).
Then there's only a single unique object referenced many (10**8
) times by the list, so there's very little to copy (the same object's refcount gets incremented and decremented many times).
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