Python:找出元组是否包含偶数的函数吗? [英] Python: Function to find out if a tuple contains even numbers?

问题描述

所以我想要的是一个函数，该函数从用户那里获取元组输入，然后确定该元组是否包含偶数.我想知道如何使用for或while循环.我已经尝试过了，但是代码不起作用.我有一些东西，但是它不起作用:

So what I want is a function that gets a tuple input from a user and then figures out if that tuple contains an even number. I want to know how to do it with a for or while loop. I've tried it but the code doesn't work. I've kind of got something but it's not working:

def ifEven(x):
    i = -1
    if isinstance(x, tuple):
        while i < len(x):
            for i in x:
                i = i + 1
                if x[i] % 2 == 0:
                    return True
                else:
                    return False 

推荐答案

您应该阅读有关Python中for语句的文档:

You should read the documentation about for statement in Python: https://docs.python.org/2/tutorial/controlflow.html#for-statements.

这是一个有效的代码:

def ifEven(x):
    if isinstance(x, tuple):
        for i in x:
            if i % 2 == 0:
                return True
    return False

话虽如此，它可以使用Python的生成器表达式重写为单行代码:

That being said, it can be rewritten as a one-liner using Python's generator expressions:

def isEven(x):
    return any(v % 2 == 0 for v in x)

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