检查上传文件数组中是否存在文件 [英] Check if file exists in the upload file array

问题描述

我在前端提交了表单来提交内容，其中我需要检查提交时文件是否存在.

I got form at frontend to submit stuff, wherein I need to check if file exists on submit.

请注意，表单提交了文件数组.它使我一直在尝试的所有逻辑都失败了.请注意html第二行上的upload[].

Please note that the form submits array of files. It is failing the all logics I have been trying. Please notice the upload[] on second line of html.

HTML

<form method="post" id="upload-form" action="" enctype="multipart/form-data" >
<input type="file" multiple="true" name="upload[]">
<input type="submit" name="upload_attachments" value="UPLOAD">
<form>

PHP

if(!file_exists($_FILES['upload']['tmp_name'].'/'.$FILES['upload']['name'])) {

   $upload_error = 'file is not set !'; 
   return; //stop further code execution 
   }else{

   //do further validation   

   }

在两种情况下，上面的代码均显示'file is not set !'，即当我单击提交"按钮而不上传文件时，以及当我选择上传文件并单击提交按钮"时.

The code above shows 'file is not set !' in both cases, that is when I hit submit button without uploading a file and when I select to upload a file and hit the submit button.

这是怎么回事，我什至在做对吗?

What is happening here, am I even doing it right?

基本上，我想在有人单击提交"按钮而不选择要上传的文件时返回文件为空"消息，并停止进一步的代码执行.

Basically I want to return a 'File Empty' message when someone hits the submit button without selecting a file to upload, and stop the further code execution.

推荐答案

$_FILES[<key>]['tmp_name']-包含服务器上的文件路径

$_FILES[<key>]['tmp_name'] - contains file path on server

$_FILES[<key>]['name']-只是原始文件名

要处理文件file[]的数组，您需要通过以下方式获取数据 $_FILES[<key>][<property>][<id>]

To address array of files file[] you need to fetch data by $_FILES[<key>][<property>][<id>]

尝试

if(!file_exists($_FILES['upload']['tmp_name'][0])) {

手册

http://www.php.net/manual/zh/features.file-upload.php

http://www.php.net/manual/zh/features.file-upload.multiple.php

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