sfWidgetFormChoice呈现为无序列表 [英] sfWidgetFormChoice rendered as an unordered list

问题描述

我正在使用symfony 1.4.3

I'm using symfony 1.4.3

是否可以通过某种方式将sfWidgetFormChoice呈现为无序列表?

Is there some way to render a sfWidgetFormChoice as an unordered list?

API中有一个名为"renderer_class"的选项，但我找不到有关它的任何文档或示例.

In the API there is an option called 'renderer_class' but I can't find any documentation or example about it.

谢谢！

推荐答案

以lib/vendor/symfony/lib/widget/sfWidgetFormSelect.class.php为例.基本上，您需要做的是实现一个扩展sfWidgetFormChoiceBase的类，并在其中编写方法render().一个最小的示例如下所示:

take a look at lib/vendor/symfony/lib/widget/sfWidgetFormSelect.class.php for example. Basically, what you need to do is implement a class that extends sfWidgetFormChoiceBase and write a method render() therein. A minimal example would look like this:

<?php
class sfWidgetFormChoiceUnordered extends sfWidgetFormChoiceBase
{
    public function render($name, $value = null, $attributes = array(), $errors = array())
    {
        $result = '<ul>'
        $choices = $this->getChoices();
        foreach ($choices as $choice) {
            $result .= '<li>' . $choice . '</li>';
        }
        return $result .= '</ul>';
    }
}

您可以将其放在/lib/widget/sfWidgetFormChoiceUnordered.class.php中.然后，您需要像已经发现的那样在sfWidgetFormChoice小部件上设置renderer_class选项.将其设置为我们刚刚编写的类的名称:sfWidgetFormChoiceUnordered.

You can put this in /lib/widget/sfWidgetFormChoiceUnordered.class.php. Then you need to set the renderer_class option on the sfWidgetFormChoice widget like you already found out. Set it to the name of the class we just wrote: sfWidgetFormChoiceUnordered.

示例:

...
$this->addWidget('choice', new sfWidgetFormChoice(array(
    'renderer_class' => 'sfWidgetFormChoiceUnordered'
));
...

有关render()参数的文档，请查看我上面发布的示例类.

For documentation on the arguments to render(), check out the example class I posted above.

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