如何创建一个基于ID的PHP表单? [英] How to create an ID based PHP form?

问题描述

我想基本上创建一个PHP表单，根据您输入的内容将数据存储到数据库中，这当然是基本的.

I want to basically create a PHP form that stores data into a database - based on what you enter - this is of course basic.

但是，有一个怪癖:

此php表单必须基于ID-提供链接.

This php form must be id based - given a link.

让我们说像mywebsite.com/form.php=id446之类的东西会生成与mywebsite.com/form.php=id447之类的东西截然不同的形式.

Let's say something like mywebsite.com/form.php=id446 will generate a much different form than something like mywebsite.com/form.php=id447.

两种形式的区别在于大约3-4个形式字段(无论它们是否出现)，其余都是相同的

The difference in both the forms is about 3-4 form fields(whether they appear or not), rest is the same

现在，我可以蛮力地制作form446.php，form447.php等-但我宁愿不这样做.

Now, I could brute force this and just make form446.php, form447.php, etc. - but I'd rather not.

那么有没有允许我执行此操作的功能?

So is there any function that allows me to do this?

还有，是否有任何模板可用于制作美观且令人赏心悦目的php表单-使它们更易于填充?

Also, is there any template for making aesthetic and eye-pleasing php forms - that make them easier to fill?

谢谢大家， xoxo

thanks guys, xoxo

推荐答案

您可以使用单个form.php，但是要使用代码中的if结构来包括/排除各个部分-就像这样:

You can use a single form.php but use if structures in the code to include / exclude the individual parts - so something like:

<form action="doForm" method="post">
    Input 1: <input type="text" id="input1"/> 
    Input 2: <input type="text" id="input1"/>

    <?php
        //This field only appears if you hit the url form.php?formid=123
        if($_GET['formid'] == 123):
        echo 'Input 3: <input type="text" id="input3"/>';
        endif;
    ?>
    <input type="submit" id="submit" value="submit" />
</form>

作为服务器端脚本语言，PHP并不是制作漂亮，可用的表单所需要的-它只关心它们的功能处理.对于漂亮的表格，您可能需要一些漂亮的HTML/CSS和javascript.有一个用于可用表单"的Google，并查看以下jQuery插件列表以获取想法:

Being a server-side scripting language, PHP isn't what you need for making pretty, usable forms - it only cares about the functional processing of them. For pretty forms, you'll probably want some nice HTML / CSS and javascript instead. Have a google for "usable forms" and check out things like this list of jQuery plugins for ideas: http://www.queness.com/post/204/25-jquery-plugins-that-enhance-and-beautify-html-form-elements

-编辑- 我是否应该假设您还需要大约10000种具有自己独特元素的不同形式?我希望不是这样(出于您自己的理智！).如果您完全可以减少这种情况，那么您可能想尝试将formType作为URL参数而不是仅作为ID添加，这样您就可以将这些解析成组了.

--- Edit ---- Should I assume you also need about 10000 different forms with their own unique elements? I hope (for your own sanity!) that's not the case. If you can reduce that at all then you might want to try adding formType as a url parameter instead of just the ID, that way you can parse those out in groups instead.

说实话，这是我无论如何都要使用数据库的工作-我将建立一个表来保存每个表单的ID号以及与其关联的元数据的另一个字段(可能是数组，甚至是序列化的大批).然后，您可以将其提取到应用程序中，并且仍然可以使用formId作为唯一的url参数.从您的其他评论中，我猜认为保存已保存数据的表不是特定于formId的，因此这可能应该可以工作.

To be honest this is the sort of job I'd use a database for anyway - I'd set up a table to hold each form's ID number and another field for its associated metadata (maybe in an array or even a serialised array). You could then extract that out in the application and you can still go by using the formId as the only url parameter. From your other comments I guess that the table that holds the saved data isn't formId specific, so this should probably work.

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