现代Fortran:从后代调用祖先过程 [英] Modern Fortran: Calling an ancestor procedure from descendent

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问题描述

我开始使用Modern Fortran的OO功能,并且已经熟悉其他语言的OO.在Delphi(对象Pascal)中,通常在其重写后代过程中调用过程的祖先版本,甚至有继承"的语言声明也允许这种情况.我找不到等效的Fortran构造-但可能正在寻找错误的东西.请参阅下面的简单示例.任何建议,不胜感激.

I am starting to use the OO features of Modern Fortran and am already familiar with OO in other languages. In Delphi (Object Pascal) it is common to call an ancestor version of a procedure in its overridden descendent procedure and there is even a language statement "inherited" that allows this. I can't find an equivalent Fortran construct - but am probably looking for the wrong thing. See simple example below. Any advice much appreciated.

type tClass
  integer :: i
contains
  procedure Clear => Clear_Class
end type tClass

type tSubClass
  integer :: j
contains
  procedure Clear => Clear_SubClass
end type tSubClass

subroutine Clear_Class
  i = 0
end subroutine

subroutine Clear_SubClass
  inherited Clear ! this is the Delphi way
  j = 0
end subroutine

推荐答案

以下是一些示例代码,试图通过@HighPerformanceMark实现注释(即,子类型具有引用父类型的隐藏组件). /p>

Here is some sample code that tries to implement the comment by @HighPerformanceMark (i.e., a child type has a hidden component that refers to the parent type).

module testmod
    implicit none

    type tClass
        integer :: i = 123
    contains
        procedure :: Clear => Clear_Class
    endtype

    type, extends(tClass) :: tSubClass
        integer :: j = 456
    contains
        procedure :: Clear => Clear_SubClass
    endtype

contains

    subroutine Clear_Class( this )
        class(tClass) :: this
        this % i = 0
    end

    subroutine Clear_SubClass( this )
        class(tSubClass) :: this
        this % j = 0
        call this % tClass % Clear()  !! (*) calling a method of the parent type
    end
end

program main
    use testmod
    implicit none
    type(tClass) :: foo
    type(tSubClass) :: subfoo

    print *, "foo (before) = ", foo
    call foo % Clear()
    print *, "foo (after)  = ", foo

    print *, "subfoo (before) = ", subfoo
    call subfoo % Clear()
    print *, "subfoo (after)  = ", subfoo
end

提供(使用gfortran-8.2)

which gives (with gfortran-8.2)

 foo (before) =          123
 foo (after)  =            0
 subfoo (before) =          123         456
 subfoo (after)  =            0           0

如果我们注释掉以(*)标记的行,则subfoo % i保持不变:

If we comment out the line marked by (*), subfoo % i is kept unmodified:

 foo (before) =          123
 foo (after)  =            0
 subfoo (before) =          123         456
 subfoo (after)  =          123           0

这篇关于现代Fortran:从后代调用祖先过程的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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