Fortran在txt文件中查找字符串 [英] Fortran find string in txt file

问题描述

我想知道如何在txt文件中查找字符串并读取其后的数字. 该文件的txt部分如下:

I would like to know how to find a string in a txt file and read the numbers after it. The txt portion of the file is like:

...
x0 1 0 1 0.5 0
dx0 0 0 1 0 0

这就是我想要做的:

character :: c
real :: v1(1:5), v2(1:5)
integer :: i
...
open(10, file="input.txt", action="read")
...
read(unit = 10, fmt=*) c
do while(c/='x')
   read(unit = 10, fmt=*) c
end do
read(unit = 10, fmt=*) c
read(unit = 10, fmt=*) v1(1), v1(2), v1(3), v1(4), v1(5)
read(unit = 10, fmt=*) c c
read(unit = 10, fmt=*) v2(1), v2(2), v2(3), v2(4), v2(5)
close(10)

是否有任何函数可以返回do-while循环找到的位置?找到这个职位的更好方法是什么?

Is there any function that returns the position the do-while loop finds? What is a better way to find this position?

谢谢

推荐答案

下面的程序显示了如何从搜索字符串为第一个单词的行中读取数字.它使用内部读取，这在Fortran I/O中通常很有用.

The program below shows how to read numbers from a line where the search string is the first word. It uses an internal read, which is often useful in Fortran I/O.

program xinternal_read
implicit none
integer :: ierr
integer, parameter :: iu = 20
character (len=*), parameter :: search_str = "dx0"
real :: xx(5)
character (len=1000) :: text
character (len=10) :: word
open (unit=iu,file="foo.txt",action="read")
do
   read (iu,"(a)",iostat=ierr) text ! read line into character variable
   if (ierr /= 0) exit
   read (text,*) word ! read first word of line
   if (word == search_str) then ! found search string at beginning of line
      read (text,*) word,xx
      print*,"xx =",xx
   end if
end do
end program xinternal_read

输出为

xx = 0. 0. 1. 0. 0.

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