带有缓冲区"fs.statSync"“错误:路径必须是不包含空字节的字符串" [英] fs.statSync with Buffer "Error: Path must be a string without null bytes"

问题描述

我已经读入了这样的文件缓冲区:

I have read in a file buffer like this:

let imageBuffer
try {
  imageBuffer = fs.readFileSync('/some/path/to/image.jpg')
} catch (e) {
  console.log('error reading in file', e)
}

然后我尝试stat缓冲区:

let imageStats = fs.statSync(imageBuffer)

我收到以下错误:

Error: Path must be a string without null bytes

但是当我查看文档时，它说statSync接受Buffer:

But when I check the documentation it says that statSync accepts a Buffer:

path: string | Buffer | URL

我再次检查了Buffer实际上是一个Buffer:

And I double checked that the Buffer is in fact a Buffer:

console.log(imageBuffer instanceof Buffer) // returns true

还检查了尺寸:

console.log(imageBuffer.byteLength) // returns 5928109 which is the correct size

那么我在这里误解了什么?您只能stat一个文件路径吗?该错误使它听起来像这样.但是文档似乎清楚地表明您也可以提供Buffer.

So what am I misunderstanding here? Can you only stat a file path? The error makes it sound this way. But the documentation seems to make it clear that you can provide a Buffer too.

还是我误会了什么?

推荐答案

我认为 fs.statSync(path) 不明确.我相信这是说它想要一个路径.路径可以是<string> | <Buffer> | <URL>，但是它必须是路径.

I think the documentation for fs.statSync(path) is ambiguous. I believe it is saying that it wants a path. The path can be <string> | <Buffer> | <URL>, but it needs to be a path.

因此，不要为它提供整个文件的缓冲区，而应为它提供一个缓冲区，如果将其转回字符串，则该缓冲区就是文件的路径.

So don't give it the buffer of the whole file, you give it a buffer that, if turned back into a string, is the path to the file.

换句话说，

• fs.statSync("C:/foo.txt");
• fs.statSync(Buffer.from("C:/foo.txt"));
• fs.statSync(new URL("/foo", "https://www.example.com");

• fs.statSync("C:/foo.txt");
• fs.statSync(Buffer.from("C:/foo.txt"));
• fs.statSync(new URL("/foo", "https://www.example.com");

考虑一下，这也是有道理的.操作系统如何为您提供有关文件原始字节的文件系统信息?一旦为字节，它将丢失文件系统的上下文.如果读入两个相同文件的内容，则它们的缓冲区将是相同的，但是任何一个的stat都将为您提供不同的结果.您要stat路径，而不是内容.

If you think about it, it makes sense too. How would an operating system be able to give you file system information about a a file's raw bytes? Once it's bytes, it loses the context of the file system. If you read in the contents of 2 identical files, their Buffers would be the same, yet the stat of either would give you different results. You want to stat a path, not contents.

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