致命错误:不能将用户类型的对象用作数组 [英] Fatal error: Cannot use object of type User as array

问题描述

应用程序上的用户通过其电子邮件登录.该电子邮件处于会话中.在本次会议上，我尝试获取有关该用户的更多信息，以在其中打印出(姓)名称和头像.当我在导航栏中执行此操作时，他做得很好，但在页面本身上，它显示以下错误:致命错误:无法将用户类型的对象用作数组"

我在做什么错了?

PHP:

$user = new User();
$email = $_SESSION['email'];
$user->getUserInfoByEmail($email);
var_dump($user['avatar']);

功能:

public function getUserInfoByEmail($email)
{
    $db = new Db();
    $select = "SELECT * FROM tblusers WHERE email = '" . $_SESSION["email"] . "';";
    $result = $db->conn->query($select);
    return $data=$result->fetch_assoc();

}

解决方案

这是因为您将$user对象用作数组(因为错误消息使完全清晰可见).

更改:

var_dump($user['avatar']);

对此:

var_dump($user->avatar);

The users on the application are logged in by their e-mail. This e-mail is in a session. With this session I try to get more information of that user to print out there (sur)names and the avatar. When I do it in my navbar he's doing it all well but on the page itself it gives the following error: 'Fatal error: Cannot use object of type User as array'

What am i doing wrong?

PHP:

$user = new User();
$email = $_SESSION['email'];
$user->getUserInfoByEmail($email);
var_dump($user['avatar']);

FUNCTION:

public function getUserInfoByEmail($email)
{
    $db = new Db();
    $select = "SELECT * FROM tblusers WHERE email = '" . $_SESSION["email"] . "';";
    $result = $db->conn->query($select);
    return $data=$result->fetch_assoc();

}

解决方案

It is because you are using the $user object as an array (as the error message makes perfectly clear).

Change:

var_dump($user['avatar']);

To this:

var_dump($user->avatar);

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