如何设置通过参数传递给函数的int值并将其分配给全局，以便我可以在函数外部使用? [英] how to set a int value passed by parameter to a function and assign it to global so I can use outside of the function?

问题描述

如何设置通过参数传递给函数的int值并将其分配给全局值，以便可以在函数外部使用?

示例:

int assignValues(int valor_assign1, valor_assign2){
    valor_assign1 = 7;
    valor_assign2 = 3;
}

  main (){  
int valor1 = 0;
int valor2 = 0;

assignValues(valor1,valor2);
printf("%d,%d",valor1, valor2);
}

输出实际上是0,0，我希望它是7,3，我该怎么做? 我知道这是一个简单的问题，但我一直在尝试和搜索，但找不到类似的内容=/ 提前致谢.

解决方案

您可以将指向整数的指针传递给函数，而不是传递值.例如:

int assignValues(int *valor_assign1, int *valor_assign2){
    *valor_assign1 = 7;
    *valor_assign2 = 3;
}

main (){  
    int valor1 = 0;
    int valor2 = 0;

    assignValues(&valor1, &valor2);
    printf("%d,%d",valor1, valor2);
}

但是，您可能想阅读指针教程.

how to set a int value passed by parameter to a function and assign it to global so I can use outside of the function?

Example:

int assignValues(int valor_assign1, valor_assign2){
    valor_assign1 = 7;
    valor_assign2 = 3;
}

  main (){  
int valor1 = 0;
int valor2 = 0;

assignValues(valor1,valor2);
printf("%d,%d",valor1, valor2);
}

The output is actually 0,0 I want it to be 7,3 how do I do this? I know its a simple question but I've been trying and searching but I can't find anything like that =/ Thanks in advance.

解决方案

You could pass a pointer to your integers into the function, instead of passing the values. E.g.:

int assignValues(int *valor_assign1, int *valor_assign2){
    *valor_assign1 = 7;
    *valor_assign2 = 3;
}

main (){  
    int valor1 = 0;
    int valor2 = 0;

    assignValues(&valor1, &valor2);
    printf("%d,%d",valor1, valor2);
}

You might want to read a pointer tutorial, however.

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