awk捕获两个模式之间重复的线组 [英] awk to capture repeating groups of lines between two patterns

问题描述

我有一个文本文件，例如:

I have a text file like:

$ cat test.txt
one
two
--------------
three
four
--------------
five
six
--------------
seven
eight
--------------
nine
ten

我正在尝试使用awk捕获--------------的两行之间的文本.

I am trying to use awk to capture the text between the two lines of --------------.

我正在尝试的输出:

$ cat test.txt
three
four

seven
eight

这是我到目前为止所拥有的

Here is what I have so far

awk '/^--------------$/{flag=1;next}/^--------------$/{flag=0}flag' test.txt
three
four
five
six
seven
eight
nine
ten

推荐答案

$ awk '{x=sub(/^-+$/,"")} f; x{f=!f}' file
three
four

seven
eight

sub()用空格替换所有---行，并保存它在x中这样做的事实，以记住当前行是---行.对于每个---行，x(f=!f}在0和1之间切换f.当f为true时，f;打印当前行，因为{print}是给定条件的默认操作.

The sub() replaces all --- lines with blanks and saves the fact it did that in x to remember that the current line was a --- line. The x(f=!f} toggles f between 0 and 1 for every --- line. The f; prints the current line when f is true since {print} is the default action given a true condition.

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