awk remote ssh命令 [英] awk remote ssh command

问题描述

我有一个运行远程awk命令的bash脚本，但是我想我没有正确地转义特殊字符，因为在远程服务器上没有文件生成.仍然我没有错误.

I have a bash script that run a remote awk command but I guess I haven't correctly escape specials characters since no file is generated on the remote server. Still I have no error.

我的变量在本地声明，可以在没有问题的情况下远程使用(脚本的其他部分确认了这一点).

My variables are declared locally and can be used remotely without issue (other part of the script confirm this).

ssh -q -t server '
        logfiles=$(find /var/log/httpd/ -type f -name *access_log -cmin -'"$past"')
        for log in $logfiles;
             awk -vDate=\`date -d'now-'"$past"' minutes' +[%d/%b/%Y:%H:%M:%S\` ' { if \(\$4 > Date\) print \$0}' $log | sort  |uniq -c |sort -n | tail | cut -d " " -f 11,15,16
        done
'

谢谢！

通过此脚本

#!/bin/bsh

logfiles=$(find /var/log/httpd/ -type f -name *access_log -cmin -120)
for log in $logfiles; do
        awk -vDate=`date -d'now-120 minutes' +[%d/%b/%Y:%H:%M:%S` ' { if ($4 > Date) print $0}' $log | sort  |uniq -c |sort -n | tail | cut -d " " -f 11,15,16 > /root/httpd.log;
done

像这样工作

ssh user @ host< script.sh

ssh user@host < script.sh

当我从控制台运行相同的脚本时:

When I run the same script from the console :

ssh -q -t $apache '     
logfiles=$(find /var/log/httpd/ -type f -name *access_log -cmin -120)
for log in $logfiles; do
awk -vDate=`date -d'now-120 minutes' +[%d/%b/%Y:%H:%M:%S` ' { if ($4 > Date) print $0}' $log | sort  |uniq -c |sort -n | tail | cut -d " " -f 11,15,16 > /root/httpd.log;
done'

    -bash: syntax error near unexpected token `('

所以我试图逃脱括号

ssh -q -t $apache '
logfiles=$(find /var/log/httpd/ -type f -name *access_log -cmin -120)
for log in $logfiles; do
awk -vDate=`date -d'now-120 minutes' +[%d/%b/%Y:%H:%M:%S` ' { if \($4 > Date\) print $0}' /var/log/httpd/royalcanin_com.access_log | sort  |uniq -c |sort -n | tail | cut -d " " -f 11,15,16 > /root/httpd.log;
done'

但是什么也没产生.

已在服务器上生成了文件，但此文件为空:

Having the file generated on the server but empty with this:

awk -vDate=\`date -d'now-120 minutes' +[%d/%b/%Y:%H:%M:%S\` ' { if '"($4 > Date)"' print $0}' $log | sort  |uniq -c |sort -n | tail | cut -d " " -f 11,15,16 > /root/httpd.log;done'

推荐答案

您还需要转义单引号.例如，第一个脚本…

You also need to escape your single quotes. For example, the first script…

ssh -q -t server '
        logfiles=$(find /var/log/httpd/ -type f -name *access_log -cmin -'"$past"')
        for log in $logfiles;
             awk -vDate=\`date -d'now-'"$past"' minutes' +[%d/%b/%Y:%H:%M:%S\` ' { if \(\$4 > Date\) print \$0}' $log | sort  |uniq -c |sort -n | tail | cut -d " " -f 11,15,16
        done
'

…必须真正写成:

ssh -q -t server '
        logfiles=$(find /var/log/httpd/ -type f -name *access_log -cmin -'\''"$past"'\'')
        for log in $logfiles;
             awk -vDate=\`date -d'\''now-'\''"$past"'\'' minutes'\'' +[%d/%b/%Y:%H:%M:%S\` '\'' { if \(\$4 > Date\) print \$0}'\'' $log | sort  |uniq -c |sort -n | tail | cut -d " " -f 11,15,16
        done
'

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