如何sed搜索将整个单词替换为文件中的字符串匹配 [英] How To Sed Search Replace Entire Word With String Match In File

问题描述

我修改了此处找到的代码: sed全字搜索并替换

I have modified the code found here: sed whole word search and replace

我一直在尝试对sed使用正确的语法\<和\>来匹配文件中的多个术语.

I have been trying to use the proper syntax \< and \> for the sed to match multiple terms in a file.

echo "Here Is My Example Testing Code" | sed -e "$(sed 's:\<.*\>:s/&//ig:' file.txt)"

但是，我认为，因为它正在查看文件，所以它与完整单词(仅完全匹配)不匹配，只剩下一些拆分单词和单个字符.

However, I think, because it's looking into the file, it doesn't match the full word (only exact match) leaving some split words and single characters.

有人知道正确的语法吗?

Does anyone know the proper syntax?

示例:

输入:

Here Is My Example Testing Code

File.txt:

example
test

所需的输出:

Here Is My Code

推荐答案

按如下所示修改您的sed命令应提取您想要的内容，

Modify your sed command as followed should extract what you want,

sed -e "$(sed 's:\<.*\>:s/&\\w*\\s//ig:' file.txt)"

简要说明，

• \b匹配单词和非字母数字字符之间的位置.在这种情况下，file.txt中的模式"test"将与"Testing"不匹配.
• 通过这种方式，修改附加了\w*的搜索模式应该可以. \w实际上与[a-zA-Z0-9_]
相匹配
• 并且不要忘记消除每个搜索模式后面的空间，应添加\s.

• \b matches the position between a word and a non-alphanumeric character. In this case, the pattern 'test' in file.txt would not match 'Testing'.
• In this way, modify the searched pattern appended with \w* should work. \w actually matched [a-zA-Z0-9_]
• And don't forget to eliminate the space behind each searched pattern, \s should be added.

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