如何使gcc忽略从未调用的函数? [英] How to make gcc ignore functions never called?

问题描述

#include <stdio.h>

void func(){
  printf("123\n");
}

int main(){
  printf("hi\n");
}

似乎无论我如何编译，func始终存在于二进制目标中?

It seems no matter how I compile it,func always exists in the binary target?

推荐答案

默认情况下，函数在C中具有外部链接.将其设为static应告知链接器外部不需要它，而应将其忽略.

Functions have extern linkage by default in C. Making it static should inform the linker it's not needed outside and it should leave it out.

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