“无法推断出通用参数".在SwiftUI UIViewRepresentable中 [英] "Generic parameter could not be inferred" in SwiftUI UIViewRepresentable

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问题描述

我有以下代码,这使得在我的SwiftUI代码中使用UIKit的UIScrollView成为可能.可以将其粘贴到新的SwiftUI项目中.

I've got the following code, which makes it possible to use the UIKit's UIScrollView in my SwiftUI code. It can be pasted in a new SwiftUI project.

struct LegacyScrollView<Content: View>: UIViewRepresentable {
    enum Action {
        case idle
        case offset(x: CGFloat, y: CGFloat, animated: Bool)
    }

    @Binding var action: Action
    let content: Content

    func makeCoordinator() -> Coordinator {
        Coordinator(self)
    }

    func makeUIView(context: Context) -> UIScrollView {
        let hosting = UIHostingController(rootView: self.content)
        hosting.view.translatesAutoresizingMaskIntoConstraints = false

        let uiScrollView = UIScrollView()
        uiScrollView.addSubview(hosting.view)

        let constraints = [
            hosting.view.leadingAnchor.constraint(equalTo: uiScrollView.leadingAnchor),
            hosting.view.trailingAnchor.constraint(equalTo: uiScrollView.trailingAnchor),
            hosting.view.topAnchor.constraint(equalTo: uiScrollView.contentLayoutGuide.topAnchor),
            hosting.view.bottomAnchor.constraint(equalTo: uiScrollView.contentLayoutGuide.bottomAnchor),
            hosting.view.widthAnchor.constraint(equalTo: uiScrollView.widthAnchor)
        ]
        uiScrollView.addConstraints(constraints)

        return uiScrollView
    }

    func updateUIView(_ uiView: UIScrollView, context: Context) {
        switch self.action {
        case .offset(let x, let y, let animated):
            uiView.setContentOffset(CGPoint(x: x, y: y), animated: animated)
            DispatchQueue.main.async {
                self.action = .idle
            }
        default:
            break
        }
    }

    class Coordinator: NSObject {
        let legacyScrollView: LegacyScrollView

        init(_ legacyScrollView: LegacyScrollView) {
            self.legacyScrollView = legacyScrollView
        }
    }

    init(@ViewBuilder content: () -> Content) {
        self._action = Binding.constant(Action.idle)
        self.content = content()
    }

    init(action: Binding<Action>, @ViewBuilder content: () -> Content) {
        self._action = action
        self.content = content()
    }
}

struct ContentView: View {
    @State private var action = LegacyScrollView.Action.idle

    var body: some View {
        VStack(spacing: 0) {
            LegacyScrollView(action: self.$action) {
                ForEach(0 ..< 40) { _ in
                    Text("Hello, World!")
                }
            }
            .padding(20)
            .background(Color.gray)
            Spacer()
            Button("Set offset") {
                self.action = LegacyScrollView.Action.offset(x: 0, y: 200, animated: true)
            }.padding()
        }
    }
}

上面的代码将在ContentView的第一行给出Generic parameter 'Content' could not be inferred.我尝试将行更改为:

The code above will give Generic parameter 'Content' could not be inferred on the first line of the ContentView. I've tried to change the line to:

@State private var action = LegacyScrollView<AnyView>.Action.idle

但是这会带来另一个错误.当我将enum Action放在struct LegacyScrollView之外时,它可以工作.但是我认为,这是对该枚举的相当小范围的界定.我该如何解决错误消息?

but that will give another error. It works when I place the enum Action outside the struct LegacyScrollView. But in my opinion, that's a rather inelegant scoping of this enum. How can I solve the error message?

推荐答案

以下是允许按原样使用提供的ContentView的方法.

Here is possible approach that allows usage of provided ContentView as-is.

只需更改...的方向,而不是使整个类型通用(在这种情况下实际上并不需要),只需对通用类型进行初始化,如下所示.

Just change the direction of... instead of making entire type generic, which is actually not needed in this case, just make a generic only initialisation, like below.

实际上,这也清楚地表明Action是与内容无关的,这确实是正确的.

Also it actually makes clear that Action is Content-independent, that is really correct.

经过测试的适用于Xcode 11.2/iOS 13.2(在ContentView中没有任何更改)

Tested & works with Xcode 11.2 / iOS 13.2 (w/o no changes in ContentView)

struct LegacyScrollView: UIViewRepresentable {
    enum Action {
        case idle
        case offset(x: CGFloat, y: CGFloat, animated: Bool)
    }

    @Binding var action: Action
    private let uiScrollView: UIScrollView

    init<Content: View>(content: Content) {
        let hosting = UIHostingController(rootView: content)
        hosting.view.translatesAutoresizingMaskIntoConstraints = false

        uiScrollView = UIScrollView()
        uiScrollView.addSubview(hosting.view)

        let constraints = [
            hosting.view.leadingAnchor.constraint(equalTo: uiScrollView.leadingAnchor),
            hosting.view.trailingAnchor.constraint(equalTo: uiScrollView.trailingAnchor),
            hosting.view.topAnchor.constraint(equalTo: uiScrollView.contentLayoutGuide.topAnchor),
            hosting.view.bottomAnchor.constraint(equalTo: uiScrollView.contentLayoutGuide.bottomAnchor),
            hosting.view.widthAnchor.constraint(equalTo: uiScrollView.widthAnchor)
        ]
        uiScrollView.addConstraints(constraints)

        self._action = Binding.constant(Action.idle)
    }

    init<Content: View>(@ViewBuilder content: () -> Content) {
        self.init(content: content())
    }

    init<Content: View>(action: Binding<Action>, @ViewBuilder content: () -> Content) {
        self.init(content: content())
        self._action = action
    }

    func makeCoordinator() -> Coordinator {
        Coordinator(self)
    }

    func makeUIView(context: Context) -> UIScrollView {
        return uiScrollView
    }

    func updateUIView(_ uiView: UIScrollView, context: Context) {
        switch self.action {
        case .offset(let x, let y, let animated):
            uiView.setContentOffset(CGPoint(x: x, y: y), animated: animated)
            DispatchQueue.main.async {
                self.action = .idle
            }
        default:
            break
        }
    }

    class Coordinator: NSObject {
        let legacyScrollView: LegacyScrollView

        init(_ legacyScrollView: LegacyScrollView) {
            self.legacyScrollView = legacyScrollView
        }
    }

}

这篇关于“无法推断出通用参数".在SwiftUI UIViewRepresentable中的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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