整数类型未按预期运行(Java) [英] Integer type not working as expected (Java)

问题描述

我正在用Java编写第一个处理泛型和标准OOP原理的程序，但是在处理Integer类型时遇到了一些问题.

I'm writing one of my first programs dealing with generics and standard OOP principles in Java, however I am running into a bit of a problem when dealing with the Integer type.

我注意到Integer应该具有一个名为compareTo(Integer anotherInteger)的方法，以便像对待int那样进行比较.

I noticed that Integers are expected to have a method named compareTo(Integer anotherInteger) in order to compare them as you would ints.

但是，当我尝试在程序中实现此方法时，遇到了问题.

However, when I tried to implement this method in my program I ran into a problem.

错误找不到符号 符号:方法compareTo(Integer) 位置:整数类型的变量x 其中Integer是类型变量:Integer扩展BinarySearchTree中声明的对象

error cannot find symbol symbol: method compareTo(Integer) location: variable x of type Integer where Integer is a type-variable: Integer extends Object declared in BinarySearchTree

基本上，我有x.comporeTo(y)，其中x& y的类型为Integer，但是未找到类型为Integer(x)的变量的compareTo方法.不确定如何解决此问题，将不胜感激.

Essentially, I have x.comporeTo(y) where x & y are of type Integer, but the compareTo method is not found for variable of type Integer (x). Not sure how to solve this, any help would be appreciated.

谢谢

我在下面提供了一个小例子来突出我的问题.我相信我正在给Integer蒙上阴影，但我不知道该如何解决或解决问题，

I've provided a small example below to highlight my problem. I believe I am shadowing Integer, but I don't know how to get around doing such, or how to fix the problem,

    public class IntgS<Integer>
    {
            Intg<Integer> z = new Intg(3);
            Intg<Integer> y = new Intg(2);
            int w = (z.getX()).compareTo(y.getX());

            public class Intg<Integer>
            {
                    private Integer x;
                    public Intg(Integer x)
                    {
                            this.x = x;
                    }

                    public Integer getX()
                    {
                            return x;
                    }
            }
    }

给出相同的错误，表示Integer类型变量z.getX()没有方法.compareTo(Integer).

This gives the same error expressing that Integer type-variable z.getX() does not have a method .compareTo(Integer).

推荐答案

根据错误消息BinarySearchTree，有一个名为Integer的类型参数，它遮盖了标准类型java.lang.Integer.

According to the error message BinarySearchTree has a type parameter called Integer which shadows the standard type java.lang.Integer.

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