坐标中的多边形 [英] polygons from coordinates
本文介绍了坐标中的多边形的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个data.frame
,其中lat
s和lng
s定义了矩形框的边界,就像这样
I've got a data.frame
with lat
s and lng
s that define the boundaries of rectangular boxes, like so
geohash north_lat south_lat east_lng west_lng
1 gbsuv 48.69141 48.64746 -4.306641 -4.350586
2 gbsuy 48.69141 48.64746 -4.262695 -4.306641
将其转换为包含POLYGON
s列的sf
对象的最简单方法是什么?
What's the easiest way to convert this into an sf
object that holds a column of POLYGON
s?
推荐答案
创建多边形的关键是坐标必须按顺序形成一个封闭区域(即,最后一个点与第一个点相同) .
The key to creating polygons is that the coordinates have to be in sequence to form a closed area (i.e., the last point is the same as the first point).
因此,您的数据将需要一些操作才能创建坐标,并将其整理好.在我的示例中,我使用lapply
So your data will need a bit of manipulation to create the coordinates, and put them in order. In my example I've done this with an lapply
然后可以从 sf示例
lst <- lapply(1:nrow(df), function(x){
## create a matrix of coordinates that also 'close' the polygon
res <- matrix(c(df[x, 'north_lat'], df[x, 'west_lng'],
df[x, 'north_lat'], df[x, 'east_lng'],
df[x, 'south_lat'], df[x, 'east_lng'],
df[x, 'south_lat'], df[x, 'west_lng'],
df[x, 'north_lat'], df[x, 'west_lng']) ## need to close the polygon
, ncol =2, byrow = T
)
## create polygon objects
st_polygon(list(res))
})
## st_sfc : creates simple features collection
## st_sf : creates simple feature object
sfdf <- st_sf(geohash = df[, 'geohash'], st_sfc(lst))
sfdf
# Simple feature collection with 2 features and 1 field
# geometry type: POLYGON
# dimension: XY
# bbox: xmin: 48.64746 ymin: -4.350586 xmax: 48.69141 ymax: -4.262695
# epsg (SRID): NA
# proj4string: NA
# geohash st_sfc.lst.
# 1 gbsuv POLYGON((48.69141 -4.350586...
# 2 gbsuy POLYGON((48.69141 -4.306641...
plot(sfdf)
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