检索泛型方法的正确超负荷的MethodInfo的 [英] Retrieving the MethodInfo of of the correct overload of a generic method
本文介绍了检索泛型方法的正确超负荷的MethodInfo的的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有这个类型包含一个通用方法的两个重载。我想找回重载之一(与 Func键<
参数; T&GT)使用反射。但问题是,我无法找到正确的参数类型与供给 Type.GetMethod(字符串类型[])
方法。
I have this type that contains two overloads of a generic method. I like to retrieve one of the overloads (with the Func<T>
parameter) using reflection. The problem however is that I can't find the correct parameter type to supply the Type.GetMethod(string, Type[])
method with.
下面是我的类定义:
public class Foo
{
public void Bar<T>(Func<T> f) { }
public void Bar<T>(Action<T> a) { }
}
这是我想出来的,可惜没有更迭:
And this is what I've come up with, unfortunately without succes:
[TestMethod]
public void Test1()
{
Type parameterType = typeof(Func<>);
var method = typeof(Foo).GetMethod("Bar", new Type[] { parameterType });
Assert.IsNotNull(method); // Fails
}
我怎样才能获得的MethodInfo
的通用方法,我知道的参数?
How can I get the MethodInfo
of a generic method of which I know the parameters?
推荐答案
你为什么不使用EX pression树?这使得它更容易:
Why don't you use expression trees? This makes it much easier:
public static MethodInfo GetMethod<T>(
Expression<Action<T>> methodSelector)
{
var body = (MethodCallExpression)methodSelector.Body;
return body.Method;
}
[TestMethod]
public void Test1()
{
var expectedMethod = typeof(Foo)
.GetMethod("Bar", new Type[] { typeof(Func<>) });
var actualMethod =
GetMethod<Foo>(foo => foo.Bar<object>((Func<object>)null)
.GetGenericMethodDefinition();
Assert.AreEqual(expectedMethod, actualMethod);
}
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