将数字列表转换为数字HASKELL [英] Convert a list of digits to a number HASKELL

问题描述

我想在haskell中创建一个函数，给出给定的一位数字列表，我将给出完整的数字.我在考虑使用密集的列表和顾客，如下所示的代码:

I want to make a function in haskell that given a list of single digits, i make the full number. I was thinking in using intensive lists and patrons, as the code it follows:

funcion5 (x:xs) = [y*(10^w) | y <- (x:xs) w]

这个想法是，遍历列表并将每个数字乘以10 pow到数字的位置.最后，我只需要对所有数字求和，就得到这样的数字:

The idea is, to go over the list and multiplie each digit to 10 pow to the position of the number. Finally i only have to sum all digits and I have the number as this:

sum (funcion5 (x:xs))

有人可以帮助我吗?谢谢

Can anyone help me, please? Thanks

推荐答案

可以简单地通过如下折叠foldl1 :: Foldable t => (a -> a -> a) -> t a -> a来完成:

This may simply be done by folding with foldl1 :: Foldable t => (a -> a -> a) -> t a -> a as follows;

Prelude> foldl1 (\x y -> 10*x+y) [1,2,3]
123

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