如何有效地将经纬度地理编码转换为行政区 [英] How to reverse geocode lat/lon into boroughs efficiently

问题描述

我正在使用纽约市出租车数据集.数据集的列包括日期时间，取货纬度/经度，落差纬度/经度等.现在，我想对纬度/经度进行反向地理编码以找到自治市/邻里.我碰到了geopy，发现类似这样的东西非常有效:

I am working with the New York City taxi data set. The data set has columns including datetime, pickup lat/lon, dropoff lat/lon etc. Now I want to reverse geocode the lat/lon to find the borough/neighborhood. I came across geopy and found that something like this worked perfectly:

from geopy.geocoders import Nominatim
geolocator = Nominatim()

borough = []
loc = ['40.764141, -73.954430', '40.78993085, -73.9496098723']
for l in loc:
    sub = str(geolocator.reverse(l))
    borough.append(sub.split(', ')[2])
borough
## ['Upper East Side', 'East Harlem']

这很完美，正是我想要的.但是，我的数据集有几百万行，并且由于这是一个在线API，因此不可行.有没有更好的方法可以做到这一点?

This is perfect, and exactly what I want. However, my dataset has a few million rows, and since this is an online API, it is not feasible. Are there any better ways to accomplish this?

推荐答案

您可以给反向地理编码器尝试一下，因为我相信它可以提供您所需的功能.
它采用纬度/经度坐标，并返回(离线)最近的城镇/城市，国家/地区，行政区域1和[ 2个地区.

You can give Reverse Geocoder a try as I believe it provides the functionality you need.
It takes a latitude / longitude coordinate and returns (offline) the nearest town/city, country, administrative 1 & 2 regions.

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