如何从另一个文件夹中减去文件夹和文件列表? [英] How to subtract folders and files list from another one?

问题描述

我有一个git repo，如下所示:

I have a git repo as below:

[root@localhost www]# tree
.
├── admin.php
├── api
    ├── index.htm
    └── remote
        └── mod
            ├── index.htm
            ├── mod_cron.php
            └── mod_index.php


3 directories, 5 files

很容易获得git跟踪的文件夹和文件的列表.

It's easy to get the list of folder and files tracked by git.

[root@localhost www]# git ls-files >a.txt
[root@localhost www]# cat a.txt
.gitattributes
.gitignore
admin.php
api/index.htm
api/remote/mod/index.htm
api/remote/mod/mod_cron.php
api/remote/mod/mod_index.php

但是在工作目录中，有些文件夹和文件没有被git跟踪.整个工作目录如下:

But in working direcotry, there's some folders and files not tracked by git.Whole working direcotry as below:

    [root@localhost www]# tree
    .
    ├── admin.php
    ├── api
    │   ├── index.htm
    │   └── remote
    │       ├── index.htm
    │       ├── index.php
    │       └── mod
    │           ├── index.htm
    │           ├── mod_cron.php
    │           └── mod_index.php
    ├── archiver
       └── index.php

4 directories, 8 files

如何获取未由git跟踪的文件夹和文件列表，如下所示::

archiver/
archiver/index.php
api/remote/index.htm
api/remote/index.php

我想在rsync -av --files-from=/path/to/not_tracked_files_lsit中使用此列表.
预先感谢！

I want to use this list in rsync -av --files-from=/path/to/not_tracked_files_lsit.
Thanks in advance!

推荐答案

基本上从上面的注释中复制...

Basically copying in from comments above...

find将为您提供完整的文件列表.

A find would give you a complete list of files present.

find | grep -v '[.]git/' | grep -vf a.txt

应该从存储库本身和所有跟踪的文件中消除废话.

should eliminate the crap from the repo itself and all the tracked files.

另一个选择，可能更好:

Another option, probably better:

git status -s | sed -n '/^[^?]/d; s/^?? //; p;'

这应该做同样的事情，但希望它可以更简洁，更精简，管线中的进程更少.

That should do much the same thing but hopefully a little cleaner and more to the point, with fewer processes in the pipeline.

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