Python argv采用通配符路径 [英] Python argv taking wild card path

问题描述

我以doc1/*.png作为第一个参数运行脚本，但该脚本被转换为doc1/image1.png.

I run my script with doc1/*.png as first argument, but it gets converted to doc1/image1.png.

如何让Python看到确切的参数?

How can I let Python see the exact argument?

img_list = []
print sys.argv[1]
x = sys.argv[1]
img_list = [img for img in glob.glob(x)]

推荐答案

在大多数Linux外壳程序(bash，sh，fish，...)上，星号由外壳程序处理. *转换为文件列表的事实已经在外壳程序级别上完成.

On most linux shells (bash, sh, fish,...), the asterisk is handled by the shell. The fact that the * is converted to a list of files is already done at the shell level.

如果您写:

python file.py doc/*.png

外壳本身会将doc/*.png转换为"doc/1.png" "doc/2.png"(因此，它在doc目录中找到的.png文件列表.

The shell itself will translate doc/*.png into "doc/1.png" "doc/2.png" (so a list of .png files it finds in the doc directory.

您应使用引号将星号传递，例如:

python file.py 'doc/*.png'

标准Windows shell 不不对文件名使用通配符.

The standard Windows shell does not do wildcards for file names.

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