还获取与fnmatch不匹配的元素 [英] Get also elements that don't match fnmatch

问题描述

我正在使用递归glob来查找文件并将文件从驱动器复制到另一个驱动器

I'm using a recursive glob to find and copy files from a drive to another

def recursive_glob(treeroot, pattern):
   results = []
   for base, dirs, files in os.walk(treeroot):

      goodfiles = fnmatch.filter(files, pattern)
      results.extend(os.path.join(base, f) for f in goodfiles)

return results

工作正常.但是我也想访问那些与过滤器不匹配的元素.

Works fine. But I also want to have access to the elements that don't match the filter.

有人可以提供一些帮助吗?我可以在循环中构建一个正则表达式，但是必须有一个更简单的解决方案，对吧?

Can someone offer some help? I could build a regex within the loop, but there must be a simpler solution, right?

推荐答案

如果顺序无关紧要，请使用一组:

If order doesn't matter, use a set:

goodfiles = fnmatch.filter(files, pattern)
badfiles = set(files).difference(goodfiles)

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