另一个类内的PHP访问类 [英] PHP access class inside another class

问题描述

所以我有两个这样的类:

So I have two classes like this:

class foo {
    /* code here */
}
$foo = new foo();
class bar {
    global $foo;
    public function bar () {
        echo $foo->something();
    }
}

我想访问所有方法栏中的foo方法，而无需在bar内的每个方法中都声明它，就像这样:

I want to access the methods of foo inside all methods bar, without declaring it in each method inside bar, like this:

class bar {
    public function bar () {
        global $foo;
        echo $foo->something();
    }
    public function barMethod () {
        global $foo;
        echo $foo->somethingElse();
    }
    /* etc */
}

我也不想扩展它.我尝试使用var关键字，但是它似乎没有用.为了访问bar所有方法中的另一个类"foo"，我该怎么做?

I don't want to extend it, either. I tried using the var keyword, but it didn't seem to work. What do I do in order to access the other class "foo" inside all methods of bar?

推荐答案

您也可以这样做:

class bar {
    private $foo = null;

    function __construct($foo_instance) {
      $this->foo = $foo_instance;
    }

    public function bar () {
        echo $this->foo->something();
    }
    public function barMethod () {
        echo $this->foo->somethingElse();
    }
    /* etc, etc. */
}

稍后您可以做到:

$foo = new foo();
$bar = new bar($foo);

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