gnuplot:在单个图中绘制来自多个输入文件的数据 [英] gnuplot : plotting data from multiple input files in a single graph

问题描述

我正在尝试使用gnuplot绘制图形.我有六个文本文件.每个文本文件包含两列.第一列表示以秒为单位的时间(浮点数).第二个是序列号.我想在所有六个文件的单个图形中绘制时间与序列号的图形.我正在使用此文件来做到这一点.

I am trying to plot a graph using gnuplot. I have six text files. Each text file contains two columns. The first column represents time in seconds (a floating point number). The second one is a sequence number. I want to plot the graph of time vs. sequence number in a single graph for all six files. I am using this file to do that.

set terminal png
set output 'akamai.png'

set xdata time
set timefmt "%S"
set xlabel "time"

set autoscale

set ylabel "highest seq number"
set format y "%s"

set title "seq number over time"
set key reverse Left outside
set grid

set style data linespoints

plot "print_1012720" using 1:2 title "Flow 1", \
plot "print_1058167" using 1:2 title "Flow 2", \
plot "print_193548"  using 1:2 title "Flow 3", \ 
plot "print_401125"  using 1:2 title "Flow 4", \
plot "print_401275"  using 1:2 title "Flow 5", \
plot "print_401276"  using 1:2 title "Flow 6"

我的文件在哪里

• print_1012720
• print_1058167
• print_193548
• print_401125
• print_401275
• print_401276

• print_1012720
• print_1058167
• print_193548
• print_401125
• print_401275
• print_401276

它给出了一个奇怪的错误，如下所示:

It is giving a strange error as below:

"plot.plt"，第24行:未定义的变量:plot

"plot.plt", line 24: undefined variable: plot

我做错什么了吗?可以在同一图中绘制来自不同文件的输入数据吗?

Am I doing something wrong? Is it possible to plot the input data from different files in the same graph?

推荐答案

您是如此亲密！

更改

plot "print_1012720" using 1:2 title "Flow 1", \
plot "print_1058167" using 1:2 title "Flow 2", \
plot "print_193548"  using 1:2 title "Flow 3", \ 
plot "print_401125"  using 1:2 title "Flow 4", \
plot "print_401275"  using 1:2 title "Flow 5", \
plot "print_401276"  using 1:2 title "Flow 6"

到

plot "print_1012720" using 1:2 title "Flow 1", \
     "print_1058167" using 1:2 title "Flow 2", \
     "print_193548"  using 1:2 title "Flow 3", \ 
     "print_401125"  using 1:2 title "Flow 4", \
     "print_401275"  using 1:2 title "Flow 5", \
     "print_401276"  using 1:2 title "Flow 6"

由于gnuplot试图将单词"plot"解释为要打印的文件名而出现错误，但是您尚未将任何字符串分配给名为"plot"的变量(这很好-太令人困惑了).

The error arises because gnuplot is trying to interpret the word "plot" as the filename to plot, but you haven't assigned any strings to a variable named "plot" (which is good – that would be super confusing).

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