在bash脚本+ gnuplot脚本中使用Gnuplot变量而不是Bash变量 [英] Use a Gnuplot variable instead of Bash Variable in a bash script + gnuplot script

问题描述

你好，我想在bash脚本中使用gnuplot绘制smth，所以我有:

Hello I want to plot smth using gnuplot in a bash script so I have:

#!/bin/bash
//myscript
gnuplot -persist <<-EOFMarker
        plot 'd.csv' using 3:xtic(1) with boxes notitle, 'd.csv' using 0:($3+100):3 with labels
EOFMarker

我的问题是脚本替代bash变量(nothing + 100)替代脚本($ 3 + 100)，而不是gnuplot替代脚本(每个值来自第三列+ 100). gnuplot?非常感谢

my problem is that the script substitute ($3+100) from bash variable (nothing+100) not from gnuplot (each value from 3rd column + 100).. how can I change the script in order to use the variable from gnuplot? thanks very much

推荐答案

它应该可以正常工作，$3为空，请考虑以下问题:

It should work, $3 is properly empty, consider this:

#!/bin/bash
set a b world
cat <<-EOF
hello $3
EOF

将输出hello world.如果要将文字$3发送到命令，则需要转义美元符号:

Will output hello world. If you want to send literal $3 to the command you will need to escape the dollar sign:

#!/bin/bash
set a b world
cat <<-EOF
hello \$3
EOF

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