gnuplot中的自动系列? [英] Automatic series in gnuplot?

问题描述

我输入的内容如下:

year   s1   s2  s3
2000   1    2   3 
2001   2    4   6 
2002   4    8   12

我不知道有多少个系列.今天是3，明天可能是4.

I don't know how many series. Today it's 3, tomorrow it may be 4.

我想将其绘制在多系列图表中.像这样:

I want to plot it in a multi-series chart. Something like this:

set key autotitle columnhead
plot 'data/chart-year-subreddit-count' using 1:2 with lines, \
'data/chart-year-subreddit-count' using 1:3 with lines, \
'data/chart-year-subreddit-count' using 1:4 with lines

除了我不知道多少列之外，我不知道在gnuplot脚本中放什么.

Except since I don't know how many columns, I don't know what to put in my gnuplot script.

我必须编写脚本来写入文件吗?还是gnuplot可以自动计算出多少个序列?

Do I have to write a script to write the file? Or can gnuplot work out how many series there are automatically?

推荐答案

Gnuplot本身无法计算列数，但是您可以使用例如wc和head计算列数:

Gnuplot itself cannot count the number of columns, but you can use e.g. wc and head to count the number of columns:

file = 'data/chart-year-subreddit-count'
cols = int(system('head -1 '.file.' | wc -w'))
plot for [i=2:cols] file using 1:i with lines

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