如何在gnuplot中绘制球体的表面? [英] How to plot the surface of a sphere in gnuplot?

问题描述

如何绘制白色球形表面?在三个维度上，半径应为1，以原点为中心.

How do I plot a white spherical surface? In three dimensions, radius should be 1, center at the origin.

我在球体上有分散的点数据.很难看清楚，因为球体另一端的点是一样可见的.因此，我想创建一个白色的球形背景"，在该背景上可以清楚地看到数据.

I have scattered point data on the sphere. It is hard to look at it, since the points from the opposite end of the sphere are just as visible. Therefore I would like to create a white spherical "background" on top of which the data is clearly visible.

将一个坐标轴的范围限制为[0:1]是很麻烦的，因为它会切断我也想看的点的一半.

Restricting the range of one coordinate axis to [0:1] is cumbersome since it cuts off half the points at which I also want to look.

坦克！

推荐答案

下面是一个示例，它是从

Here is an example, borrowed from the gnuplot demo page. For a white sphere, replace yellow with white:

set parametric
set isosamples 50,50
set hidden

R = 1.   # radius of sphere
set urange [-pi/2:pi/2]
set vrange [0:2*pi]
splot R*cos(u)*cos(v),R*cos(u)*sin(v),R*sin(u) w l lc rgb "yellow", \
"-" w p
1 0 0
-1 0 0
e

您会看到两个数据点中只有一个可见，而另一个隐藏在球体后面.

You can see that only one of the two data points is visible, while the other is hidden behind the sphere.

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