Gnuplot:第0行:用于绘制预期的函数 [英] Gnuplot: line 0: function to plot expected

问题描述

我有一个python脚本，可以使用gnuplot生成图形.但是我有一个错误:

I've a python script who generate a graphic with gnuplot. But I've an error:

gnuplot>情节 ^ 第0行:用于绘制预期的函数

gnuplot> plot ^ line 0: function to plot expected

    g=Gnuplot.Gnuplot(persist=1)
    g.title('Read&Write Performance')
    g.xlabel('minutes')
    g.ylabel('MB/s')
    g('set term png')
    g('set out')
    g('set yrange [0:70]')
    d1=Gnuplot.Data(self.time,self.list1,title="perfr", with_="line")
    d2=Gnuplot.Data(self.time,self.list2,title="perfw", with_="line")
    time.sleep(2)
    g.hardcopy('bench.png',terminal = 'png')
    g.reset()

self.list1 = [12、15、17] self.list2 = [43，48，49]

self.list1= [12, 15, 17] self.list2 = [43, 48, 49]

我不明白为什么会出现此错误.

I don't understand why I've this error.

谢谢:)

推荐答案

非常简短之后，查看源代码，看来g.plot()不会将绘图发送到窗口(例如x11)，但可以将gnuplot当前配置为发送绘图的任何地方.因此，(我认为)最简单的解决方案是-

After a very brief look at the source, it seems that g.plot() does not send the plot to a window (e.g. x11), but to wherever gnuplot is currently configured to send the plot. So, (I think) the easiest solution is --

g('set terminal png')
g('set output "bench.png"')
g.plot(d1)  #d1 should not be in "bench.png"
#This might work to plot both datasets together ... g.plot(d1,d2)  

只要发出plot命令，只要gnuplot-py的内部结构不重置gnuplot脚本，此方法就应该起作用.我非常怀疑是这种情况，因为__call__方法似乎是API中如此重要的部分.

This should work as long as the internals of gnuplot-py don't reset the gnuplot script whenever a plot command is issued. I highly doubt this is the case since the __call__ method seems to be such an important part of the API.

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