检查指定名称的屏幕是否存在 [英] Checking if a Screen of the Specified Name Exists
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问题描述
我已经制作了一个bash文件,该文件将在一个具有唯一名称的分离屏幕中启动另一个bash文件,我需要确保该内部bash文件的仅一个实例在任何时间点都在运行.为此,我想在尝试创建父bash文件之前检查该名称的屏幕是否存在.有没有办法做到这一点?
I have made a bash file which launches another bash file in a detached screen with a unique name, I need to ensure that only one instance of that internal bash file is running at any one point in time. To do this, I want to make the parent bash file check to see if the screen by that name exists before attempting to create it. Is there a method to do this?
推荐答案
您可以grep screen -list
的输出作为要检查的会话的名称:
You can grep the output of screen -list
for the name of the session you are checking for:
if ! screen -list | grep -q "myscreen"; then
# run bash script
fi
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