打印时如何取消对字段的引用? [英] How to dereference fields when printing?

问题描述

http://play.golang.org/p/joEmjQdMaS

package main

import "fmt"

type SomeStruct struct {
    somePointer *somePointer
}
type somePointer struct {
    field string
}

func main() {
    fmt.Println(SomeStruct{&somePointer{"I want to see what is in here"}})
}

这会打印一个像这样的内存地址{0x10500168}

This prints a memory address like this {0x10500168}

有没有办法打印它?

{{"I want to see what is in here"}}

这主要是出于调试目的，如果我有一个带有30个指针字段的结构，我不想为这30个字段中的每一个都做一个println来查看其中的内容.

This is mostly for debugging purposes, if I had a struct with 30 pointer fields, I didn't want to have to do a println for each of the 30 fields to see what is in it.

推荐答案

有一个很棒的软件包，叫做 go-spew .正是您想要的.

There is a great package called go-spew. Does exactly what you want.

package main

import (
  "github.com/davecgh/go-spew/spew"
)

type (
  SomeStruct struct {
    Field1 string
    Field2 int
    Field3 *somePointer
  }
  somePointer struct {
    field string
  }
)

func main() {
  s := SomeStruct{
    Field1: "Yahoo",
    Field2: 500,
    Field3: &somePointer{"I want to see what is in here"},
  }
  spew.Dump(s)

}

将为您提供此输出:

(main.SomeStruct) {
 Field1: (string) "Yahoo",
 Field2: (int) 500,
 Field3: (*main.somePointer)(0x2102a7230)({
  field: (string) "I want to see what is in here"
 })
}

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