如何将int slice的字符串转换为int slice? [英] How do I convert string of int slice to int slice?

问题描述

示例输入:(类型:string)

"[156, 100, 713]"

转换示例:(类型:int的切片)

Example conversion: (type: slice of int)

[156, 100, 713]

推荐答案

除了mhutter的回答，还请注意您输入的string看起来像一个JSON数组(也许是来自JSON文本?).

In addition to mhutter's answer, also note that your input string looks like a JSON array (maybe it is from a JSON text?).

如果这样处理，则可以将其内容编组为[]int片.直接从中解析数字的速度不会更快(如 encoding/json 包使用反射)，但肯定更简单:

If you treat it like that, you may unmarshal its content into an []int slice. This won't be faster that directly parsing the numbers from it (as the encoding/json package uses reflection), but it is certainly simpler:

s := "[156, 100, 713]"

var is []int
if err := json.Unmarshal([]byte(s), &is); err != nil {
    panic(err)
}

fmt.Println(is)
fmt.Printf("%#v", is)

输出(在转到操场上尝试):

[156 100 713]
[]int{156, 100, 713}

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