在具有多个输入的自定义函数中支持数组 [英] Supporting arrays in custom functions with multiple inputs

问题描述

我在Google Apps脚本中有一个自定义函数，该函数带有两个变量.我希望此函数采用两个数组作为参数，但是放置如果input.map，return input.map(function)"的标准方法不适用于两个变量.

I have a custom function in my google apps script that takes two variables. I want this function to take two arrays for parameters, but the standard approach of putting "if input.map, return input.map(function)" doesn't work with two variables.

我尝试通过输入递归，但是由于函数中有两个，所以不能同时使用这两个.

I have tried recursing through the inputs, but since there are two in the function, it does not work with both.

这不是我正在使用的功能，但存在相同的问题.

this is not the function i am using, but it has the same problem.

function multiply(x,y)
{
    if (x.map){
    return x.map(multiply)
    }
    if (y.map){
    return y.map(multiply)
    }
    return x * y
}

我希望公式采用两个数组(即A1:A5，B1:B5)并对每个变量执行函数-即返回A1 * B1，A2 * B2等.

I expect the formula to take two arrays (i.e. A1:A5, B1:B5) and perform the function on each variable -- i.e. returning A1 * B1, A2 * B2 etc.

推荐答案

问题:

• multiply接收两个参数.当multiply作为Array.map的函数参数提供时，第一个参数将是在其上调用map的数组的元素，第二个参数将是元素的索引.

Issue:

• multiply receives two arguments. When multiply is provided as a function argument to Array.map, the first argument will be the element of the array on which map is called and the second argument will be the element's index.
• 仅在第一个数组x上使用map，然后使用相应的第二个数组y
中的元素
• Use map only on the first array x and then use elements from the corresponding second array y

function multiply(x, y) {
  if (x.map) {
    return x.map(function(xEl, i) {
      yEl = y.map ? y[i] : y; // corresponding y Element
      return multiply(xEl, yEl);
    });
  }
  if (y.map) {//used, when y is a array and x is number
    return multiply(y, x);
  }
  return x * y;// default 
}

a = [[1],[2]];
b= [[3],[4]];
c= [[5,6],[7,8]];
d= [[1,2],[3,4]];
console.log(JSON.stringify(multiply(a,b)));
console.log(JSON.stringify(multiply(a,5)));
console.log(JSON.stringify(multiply(5,b)));
console.log(JSON.stringify(multiply(c,d)));
console.log(JSON.stringify(multiply(c,2)));
console.log(JSON.stringify(multiply(a,c))); //trims c
console.log(JSON.stringify(multiply(c,a)));//throws error

• Array#map

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