Google Apps脚本-读取电子表格数据，循环并写回数据 [英] Google Apps Script - Read spreadsheet data, loop, and write data back

问题描述

我正在寻找一些帮助，以逐行遍历电子表格中的一组数据，然后将第一个单元格中的值写入新工作表，然后将各行中的每个单元格值写入.

I'm looking for some help on looping through a set of data in a spreadsheet by row, then write the value in the first cell to a new sheet followed by each cell value across the rows.

此处是指向样本数据集的链接. 示例数据

Here is a link to a sample set of data. Sample Data

Sheet1显示原始数据.我想读入该数据并将其写入第二页(2)，以使它看起来像上述链接的第二页一样.

Sheet1 on the above spreadsheet shows the raw data. I want to read in that data and write it to sheet two (2) so that it looks like what is on sheet 2 of the above link.

这是我当前拥有的代码，但是它将所有数据写到单个列中.

Here is the current code I have but it writes all data into a single column.

function myfunction() {
  var sheet = SpreadsheetApp.getActiveSheet();
  var sheet2 = 
      SpreadsheetApp.getActiveSpreadsheet().getSheetByName('Sheet2');
  var data = sheet.getDataRange().getValues();
  for (var i = 0; i < data.length; i++)  {
    for (var j = 0; j < data[i].length; j++) {
      var iava_value = (data[i][0]);
      var lastRow = sheet2.getLastRow();           
      sheet2.getRange(lastRow +1, +1).setValue(data[i][j]);
    }
  }
}

推荐答案

这是我尝试执行的工作版本.

Here is a working version of what I was trying to do.

function transpose() {
  var sheet = 
     SpreadsheetApp.getActiveSpreadsheet().getSheetByName('Sheet1');
  var sheet2 = 
     SpreadsheetApp.getActiveSpreadsheet().getSheetByName('Sheet2');
  var data = sheet.getDataRange().getValues();  
  var myRA = new Array(2); 
  for (var i = 0; i < data.length; i++)  {
    //GET IAVA No
  var iava_no = data[i][0];    

    for (var j = 1; j < data[i].length; j++) {
      var plugin_id = (data[i][j]);      

    if(plugin_id === ""  || plugin_id =="n"  || plugin_id == "a"){        
     break;        
    }
    else
    {
    Logger.log(plugin_id);
    var lastrow = sheet2.getLastRow();      
    sheet2.getRange(lastrow + 1, 1).setValue(data[i][0]);        
    sheet2.getRange(lastrow + 1, 2).setValue(data[i][j]);
   }
 }
 }
 }

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