弹出拦截器API-如何检查用户是否已启用它 [英] Pop up blocker API- how to check if user has it enabled

问题描述

我需要知道用户何时单击触发window.open的按钮，是否存在稳定的API/方式，以便事先了解用户是否主动具有弹出窗口阻止程序?

I need to know when the user clicks on the button that triggers window.open if there is stable API/way to know beforehand if the user actively has a pop-up blocker?

在某些情况下，用户不知道/没有注意他们有弹出窗口阻止程序(阻止了新窗口).我想通过单击一些对话框来通知他们，或者通过单击允许来授权一个新窗口.

In some cases the user doesn't know/pay attention that they have pop-up blocker (that block the new window). I would like to inform them by some dialog/or something to authorize a new window by clicking on allow.

推荐答案

Window.open(...)返回到新窗口的句柄(如果存在).如果它没有新窗口的句柄，则很好地表明该窗口已被阻止.

Window.open(...) returns a handle to the new window if it exists. If it doesn't have a handle to the new window, that's a pretty good indication the window was blocked.

https://developer.mozilla.org/en-US/docs/Web /API/Window/open

来自: https://davidwalsh.name/popup-block-javascript

var windowName = 'userConsole'; 
var popUp = window.open('/popup-page.php', windowName, 'width=1000, height=700, left=24, top=24, scrollbars, resizable');
if (popUp == null || typeof(popUp)=='undefined') {  
    alert('Please disable your pop-up blocker and click the "Open" link again.'); 
} 
else {  
    popUp.focus();
}

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