Google Closure编译器包括 [英] Google Closure Compiler Includes

问题描述

我在我的项目中一直使用google封闭编译器，太棒了！

我一直试图找出您是否可以在包含其他JavaScript文件的javascript文件中执行包含"操作.我正在尝试让1个javascript文件包含"我需要的所有文件，然后进行编译，就像您可以使用LESS导入语句(例如，"@ import"../less/bootstrap")一样.

这可能吗? -还是在编译时必须在命令行中提供源文件列表?

非常感谢！

解决方案

使用Closure-Library时

包含"通过goog.require调用进行处理.请参见 https://developers.google.com/closure/library/docs/tutorial# zippy

在未编译的代码中，包含的脚本是动态插入的.在编译过程中，编译器将包含所有必需的脚本，而消除死代码将删除未使用的方法和符号.

其他选项

用于处理JavaScript包含/依赖项的最流行的选项是 RequireJS . RequireJS执行动态脚本插入. Closure-compiler具有Common JS pass，可将RequireJS require调用转换为goog.require调用，以便编译器可以在编译期间直接包括它们.

I've been using google closure compiler for a little bit with my projects, it's awesome!

I've been trying to find out whether or not you can do "includes" in a javascript file that includes other javascript files. I'm trying to have 1 javascript file that "includes" all the files I need then compiles, much like you can do with a LESS import statement, ("@import "../less/bootstrap") for example.

Is this possible? - Or do you have to provide the list of source files at time of compilation in the command line?

Many thanks!

解决方案

When Using Closure-Library

"Includes" are handled via goog.require calls. See https://developers.google.com/closure/library/docs/tutorial#zippy

In un-compiled code, the included scripts are dynamically inserted. During compilation, the compiler will include all the necessary scripts and dead-code elimination will remove the unused methods and symbols.

Other Options

The most popular option for handling JavaScript includes/dependencies is RequireJS. RequireJS does dynamic script insertion. Closure-compiler has a Common JS pass which translates RequireJS require calls to goog.require calls so that the compiler can then include them directly during compilation.

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