在Firestore Cloud函数中通过其uid获取身份验证用户 [英] Get a auth user by its uid in Firestore cloud function
问题描述
当将新对象添加到集合中时,我会触发云功能.看起来像这样:
I have cloud function triggered when a new object is added to a collection. It looks like this:
exports.emailAdmin = functions.firestore
.document('user-books/{userId}/books/{ASIN}')
.onWrite(event => {
event.data.data()
是添加到子集合(书")的对象. userId
来自Firebase身份验证系统. IE.用户登录,并使用其"uid"将一个对象添加到用户书"集合中.
That event.data.data()
is an object added to the sub-collection ("books"). The userId
comes from the Firebase authentication system. I.e. a user signed in, and added an object to the collection "user-books" with his/her "uid".
我尝试过:
firestore
.collection('users')
.doc(uid)
.get()
但是,当然"失败了,因为 I 没有名为"users"的集合.如何进入身份验证数据库"?
But that, "of course", fails because I don't have a collection called "users". How do I get to the "authentication database"?
目的是将"uid"转换为该人的电子邮件".
The purpose is to convert the "uid" to that person's "email".
推荐答案
导入firebase-admin:
Import firebase-admin:
import * as admin from 'firebase-admin';
然后获取身份验证用户:
Then fetch the auth user:
const uid = ...;
const authUser = await admin.auth().getUser(uid); // this returns a promise, so use await or .then()
console.log(authUser.email);
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