使用Google OpenID的PHP编辑帖子 [英] PHP Edit Post with Google OpenID
问题描述
我正在尝试为我的网站编写一个编辑帖子页面，该页面使用google openid登录到自己的网站，但是我只得到一个空白页面，而不是编辑表单.这是我正在使用的代码:
I'm trying to code an edit post page for my site which posts to itself using a google openid logon, however i just get a blank page, instead of the edit form. Here's the code i'm using:
<html>
<head>
<title>BQuotes</title>
<!-- <meta name="viewport" content="width=device-width, initial-scale=1"> -->
<meta name="viewport" content="width=device-width, initial-scale=1.0, maximum-scale=1.0, user-scalable=no" />
<link href="votingfiles/voting.css" rel="stylesheet" type="text/css" />
<script src="votingfiles/voting.js" type="text/javascript"></script>
<link rel="stylesheet" href="http://code.jquery.com/mobile/1.4.2/jquery.mobile-1.4.2.min.css" />
<link rel="stylesheet" type="text/css" href="http://bquotes.me/mystyle-a.css">
<script src="http://code.jquery.com/jquery-1.10.0.min.js"></script>
<script src="http://code.jquery.com/mobile/1.4.2/jquery.mobile-1.4.2.min.js"></script>
<style>
.head_text {
color: #ffffff;
}
a {
text-decoration: none;
}
</style>
<script type="text/javascript">
$('#g-login').bind('click', function (event) {
// event.preventDefault();
// $('#form-id').attr('action', 'google-login.php').trigger('submit');
alert("Clicked");
});
</script>
</head>
<body style="color:#d4ffaa">
<!-- BQ Edit Post Start -->
<div data-role="page" id="editPost">
<div data-role="header" style="background-color:#5FBF00">
<h1 class="head_text">BQuotes: Edit Statuses</h1>
</div>
<div data-role="main" class="ui-content">
<?php
?>
</div>
<?php
define ('HOSTNAME', 'host');
define ('USERNAME', 'user');
define ('PASSWORD', 'pass');
define ('DATABASE_NAME', 'db');
$db = mysql_connect(HOSTNAME, USERNAME, PASSWORD) or die ('I cannot connect to MySQL.');
mysql_select_db(DATABASE_NAME);
$tbl='table';
$id=$_POST['pid'];
$query="SELECT * from $tbl WHERE $id=id";
$result = mysql_query($query);
while($row = mysql_fetch_array($result)) {
$id=$row['id'];
$username=$row['username'];
$message=$row['message'];
$tag=$row['tag'];
session_start();
if($_SESSION['myusername'] != null && isset($_SESSION['myusername'])){
echo "<form action='logout.php' method='post' id ='form-logout' data-ajax='false'>
<br/><input type='submit' value='Logout'/>";
echo "</form>";
echo "<div style='margin-left:20px;'>Logged In As: ".$_SESSION['myusername']."</div>";
echo "<form name='post-edit' action='' method='post'>";
echo "<input type='hidden' name='id' value=".$row['id'].">";
echo "<input type='hidden' name='username' value=".$row['username'].">";
echo "<textarea name='message' value=".$row['message'].">";
echo "<input type='text' name='tag' value=".$row['tag'].">";
echo "<input type='submit' name='submit' value='Edit!'>";
echo "</form>";
}
else if($_SESSION['myusername'] == null){
echo "<form action='google-login.php?login=true' method='post' id ='form-id' data-ajax='false'>";
echo "<span class='loginreq'>Login to Edit</span>";
echo "<br/><input type='submit' value='Login with Google'/>";
echo "</form>";
}
}
if (isset($_POST['submit'])) {
$query = "UPDATE mybq_post_txt_main SET message=$message, tag=$tag WHERE id=$id ";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result)) {
echo "Your post has been edited to:";<br>
echo $row['message'];
echo $row['tag'];
}
mysql_free_result($result);
mysql_close();
}
?>
<a href='mybq-index.php'>Home</a>
</div>
</body>
</html>
任何帮助将不胜感激. (不要管PHP SQL语句，稍后我将把它们转换为PDO.)
Any help will be appreciated. (never mind the PHP SQL statements, I will convert them to PDO later).
推荐答案
此处是有效的代码(代码段下方的完整代码).
最初的错误是您的帖子已被编辑为:"后的换行符(<br>)，该格式未正确设置为php.
其他错误是正确地关联了$ _GET变量，错误的表名以及初始的"while"条件的错误循环.
Here is the code that worked (The Full code below the snippet).
The initial bug was the line break ( <br> ) after the "your post has been edited to:" which was not properly formatted for php.
The other bugs were relating the $_GET variable properly, wrong table name, and wrong looping of the initial 'while' condition.
谢谢！
这篇关于使用Google OpenID的PHP编辑帖子的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
