Google Sheeet API的问题 [英] Issue with Google Sheeet API
问题描述
我正在尝试使Web服务能够使用PHP写入GoogleSheet API.
I am trying to make web service to write into GoogleSheet API with PHP.
为此,我正在关注Google控制台的文档
for that, I am following the documentation of google console
并编写以下代码
<?php
require __DIR__ . '/vendor/autoload.php';
if (php_sapi_name() != 'cli') {
throw new Exception('This application must be run on the command line.');
}
function getClient()
{
$client = new Google_Client();
$client->setApplicationName('Google Sheets API PHP Quickstart');
$client->setScopes(Google_Service_Sheets::SPREADSHEETS);
$client->setAuthConfig('credentials.json');
$client->setAccessType('offline');
$client->setPrompt('select_account consent');
$tokenPath = 'token.json';
if (file_exists($tokenPath)) {
$accessToken = json_decode(file_get_contents($tokenPath), true);
$client->setAccessToken($accessToken);
}
if ($client->isAccessTokenExpired()) {
if ($client->getRefreshToken()) {
$client->fetchAccessTokenWithRefreshToken($client->getRefreshToken());
} else {
$authUrl = $client->createAuthUrl();
printf("Open the following link in your browser:\n%s\n", $authUrl);
print 'Enter verification code: ';
$authCode = trim(fgets(STDIN));
$accessToken = $client->fetchAccessTokenWithAuthCode($authCode);
$client->setAccessToken($accessToken);
if (array_key_exists('error', $accessToken)) {
throw new Exception(join(', ', $accessToken));
}
}
if (!file_exists(dirname($tokenPath))) {
mkdir(dirname($tokenPath), 0700, true);
}
file_put_contents($tokenPath, json_encode($client->getAccessToken()));
}
return $client;
}
$client = getClient();
$service = new Google_Service_Sheets($client);
$spreadsheetId = 'XXXX';
$range = 'Class Data!A2:E';
$response = $service->spreadsheets_values->get($spreadsheetId, $range);
$values = [["This","is","a","new","row"],];
$body = new Google_Service_Sheets_ValueRange([
"values" =>$values
]);
$params = [
"valueInputOption" => "RAW",
"insertDataOption" => "INSERT_ROWS"
];
$result = $service->spreadsheets_values->append(
$spreadsheetId,
$range,
$body,
$params
);
但是当我运行这段代码时,这给了我下面给出的错误.
But when I run this code this gives me the error which is given below.
[25-Nov-2019 01:53:03美国/芝加哥] PHP致命错误:未捕获的异常"Exception",消息为此应用程序必须在命令行上运行".在Google_sheet/quickstart.php:5中 堆栈跟踪:
[25-Nov-2019 01:53:03 America/Chicago] PHP Fatal error: Uncaught exception 'Exception' with message 'This application must be run on the command line.' in Google_sheet/quickstart.php:5 Stack trace:
thrown in Google_sheet/quickstart.php on line 5
您能帮我吗
推荐答案
它说得很清楚:
此应用程序必须在命令行上运行.
This application must be run on the command line.
因此,这意味着您未使用命令行运行它,而是尝试使用浏览器访问它.如果您按照快速入门指南所述:
So, this means you are not running it using the command line, you are trying to access it using the browser. If you do as the quickstart guide says:
php quickstart.php
然后它将起作用.
为什么使用浏览器访问时会看到此异常?
由于以下行位于代码的开头:
Because of this lines placed at the beginning of your code:
if (php_sapi_name() != 'cli') {
throw new Exception('This application must be run on the command line.');
}
要在浏览器上运行该怎么办?
只需删除这些行,您就可以使用浏览器运行脚本.
Just remove those lines and you'll be able to run the script using the browser.
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